Answer:
27.025 g of H₂O
Explanation:
The Balance chemical equation is
2 H₂ + O₂ = 2 H₂O
Step 1: Calculate Limiting Reagent
Moles of H₂
Mole = 16 g / 2.02 g/mol = 7.937 mol
Moles of O₂
Mole = 24 g / 32.00 g/mol = 0.750 mol
Mole ratio of H₂ : O₂ is 2 : 1. Hence, 7.937 mol of H₂ will need 3.9685 mol of O₂. This means O₂ is limiting reagent.
Step 2: Calculate Moles of H₂O
0.750 mol of O₂ will produce 1.50 mol of H₂O because the mole ratio of O₂ : H₂O is 1 : 2.
Step 3: Calculate mass of H₂O
Mass = 1.50 mol × 18.02 g/mol = 27.025 g of H₂O
