Answer:
Iron
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Answer:
A thermochemical equation for the combustion of propane (C3H8)(C3H8) is written as follows:
C3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔH∘rxnC3H8(l)+5O2(g)→3CO2(g)+4H2O(g);ΔHrxn∘ = -2202.0 kJ/mol
The value given for ΔH∘rxnΔHrxn∘ means that:
a. the reaction of one mole of propane absorbs 2202 kJ of energy from the surroundings.
b. the reaction is endothermic.
c. the enthalpy of formation of propane is 2202 kJ/mol.
d. the reaction of one mole of propane releases 2202 kJ of energy to the surroundings.
e. None of these.
The best option i think is b would be my best answer
1 mmol --------------------- 1000 <span>µmol
( mmol ) -------------------- </span> 38231 µmol
mmol = 38231*1 / 1000
mmol = 38231/ 1000
=> 38.231 mmol
I 90% sure that it would be supersaturated