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topjm [15]
3 years ago
14

Write a function named firstLast2 that takes as input an array of integers and an integer that specifies how many entries are in

the array. The function should return true if the array starts or ends with the digit 2. Otherwise it should return false. Test your function with arrays of different length and with the digit 2 at the beginning of the array, end of the array, middle of the array, and missing from the array.
Computers and Technology
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

<em>Written in C++</em>

#include<iostream>

using namespace std;

int firstLast2(int arr[], int n);

int main()

{

int n;

cout<<"Number of Elements: ";

cin>>n;  

int myarray[n];

for(int i = 0; i<n;i++) {

cin>>myarray[i];

}

firstLast2(myarray, n);

return 0;

}

int firstLast2(int arr[], int n){

if(arr[0] == 2 || arr[n - 1] == 2) {

 cout<<"True";

}

else {

cout<<"False";

}

}

Explanation:

<em>I've added the full source code as an attachment where I used comments to explain difficult lines</em>

Download cpp
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Answer: Strong 128-bit encryption.

Explanation: An individual character corresponds to 8 bits . So if there are 16 characters then,

16\times8=128 bits keys

This makes the 128 bit key encryption the strongest amongst all other options.It is strongest because it is almost impossible to decode the 128-character key  by any method e.g.-brute-force method.

Other options are incorrect because the characters given by the other bits are as follows:  {\frac{256}{8}=32 characters

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Answer:

The program to this question can be given as:

Program:

factorial=1 #declare a variable.  

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Explanation:

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  • Then we define a loop in the loop we calculate the factorial and hold the value in the factorial value in the last we print the value.  

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