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Mariana [72]
3 years ago
7

Solve for c: 2/3 c=d

Mathematics
1 answer:
Marizza181 [45]3 years ago
8 0
 2/3 c = d
multiply both sides by 3/2:-

c = (3/2) d
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type the correct answer in the box. use numerals instead of words. what value of x makes this equation true? x/6 - 7 = -4
Vilka [71]

\dfrac{x}{6}-7=-4\\\dfrac{x}{6}=3\\x=18

6 0
3 years ago
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Suppose<br> cos(π/2−x) =3/5, cos x =4/5<br> find sin, tan, csc, sec, cot
Pani-rosa [81]
Cos (π/2 - x) = sin x = 3/5
tan x = sin x / cos x = 3/5 / 4/5 = 3/4
csc x = 1/sin x = 1 / 3/5 = 5/3
sec x = 1/cos x = 1 / 4/5 = 5/4
cot x = 1/tan x = 1 / 3/4 = 4/3.
5 0
3 years ago
Please help me finish these for summer school :)
ValentinkaMS [17]
13.45 will be the answer

since we are finding the hypotenuse, the formula is a^2 + b^2 = c^2

this will then be 10^2 + 9^2 = c^2

181=c^2

c=13.45 :)
5 0
2 years ago
Read 2 more answers
Please answer and show work.
andrew11 [14]
Simplifying
9 + -2x = 35

Solving
9 + -2x = 35

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9' to each side of the equation.
9 + -9 + -2x = 35 + -9

Combine like terms: 9 + -9 = 0
0 + -2x = 35 + -9
-2x = 35 + -9

Combine like terms: 35 + -9 = 26
-2x = 26

Divide each side by '-2'.
x = -13

Simplifying
x = -13
4 0
3 years ago
Fill in the blank. Given O below, you can conclude that OD is congruent to ___________.
Debora [2.8K]

The circle with center O has two chords AC and EF which are of same length 9.07.

OD and OB are the two perpendiculars drawn from the center O to the two chords AC and EF .It represents the distance of the chords from the centre.

The circle theorem states: congruent chords are equidistant from the center.

OD is congruent to OB.

Option A is the right answer.

4 0
3 years ago
Read 2 more answers
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