When we want to find the distance between two integers using the difference, the best way is to plot them on number line. And then count distance between them. For example -3 and -1. But distance can not be negative.
All of the steps are good up until the 25-0, instead a 0 should have put into the top and the 1 brought down so that it was 251-248 which gets you 3 as a remainder so the answer is 804 R3
Answer:
27
Step-by-step explanation:
easy
theta is in the fourth quadrant where the cosine is positive.
the third side in the triangle = sqrt (4 - 2) = sqrt2
So sin theta = -sqrt2/2 = Second choice (negative because sine is negative in 4th quadrant)
tan theta = - sqrt2 / sqrt2 = -1
Answer:
Step-by-step explanation:
![\sqrt[3]{-\frac{1}{512}}=\frac{\sqrt[3]{-1}}{\sqrt[3]{512}}=\frac{-1}{8}=-\frac{1}{8}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-%5Cfrac%7B1%7D%7B512%7D%7D%3D%5Cfrac%7B%5Csqrt%5B3%5D%7B-1%7D%7D%7B%5Csqrt%5B3%5D%7B512%7D%7D%3D%5Cfrac%7B-1%7D%7B8%7D%3D-%5Cfrac%7B1%7D%7B8%7D)
