Divide. (4x² +17x+20) / (x+3)

Three people divide up a large pizza. If the first person gets half and the second person gets half as much as the first person

Eduardwww [97]

So, if the first person takes half of the pizza, half of the pizza is left.
If the second person takes half of the amount the first person took, that would be a quarter of the pizza left.

TL;DR - There is 1/4 of the pizza left

7 0

3 years ago

Can someone help me the 2nd problem I don’t understand it

Galina-37 [17]

Answer:

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

270 miles

Step-by-step explanation:

So is A is going faster than B so A will reach the destination first.

When will A reach it's destination?

Let's find out.

To solve this problem, the following will come in handy:

Speed=distance/time or time*Speed=distance or time=distance/speed .

time=distance/speed

$T_A=\frac{390}{S_A}$

$T_A=\frac{390}{65}$

$T_A=6$

So it will take bus A 6 hours to cover the distance of 390 miles.

How much time would have it taken bus B to reach that same distance?

$T_B=\frac{390}{45}$

$T_B=8.\overline{6}$

So it would have taken bus B $8.\overline{6}$ hours to cover a distance of 390 miles.

So the time difference is $8.\overline{6}-6=2.\overline{6}$ hours.

It will take $2.\overline{6}$ more hours than bus A for bus B to complete a distance of 390 miles.

So bus B traveled $2.\overline{6} \cdot 45=120$ miles (used the time*speed=distance) after bus A got to it's destination.

So this means the bus B covered 390-120=270 miles when bus A has already reached 390 miles.

4 0

3 years ago

Match each equation with its solution set. Tiles a2 − 9a + 14 = 0 a2 + 9a + 14 = 0 a2 + 3a − 10 = 0 a2 + 5a − 14 = 0 a2 − 5a − 1

sattari [20]

We have that

N 1)
a² − 9a + 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 9a)=-14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² − 9a+20.25)=-14+20.25

Rewrite as perfect squares

(a-4.5)²=6.25--------> (a-4.5)=(+/-)√6.25

a1=4.5+√6.25-----> a1=7

a2=4.5-√6.25-----> a2=2

the solution problem N 1 is the pair {7, 2}

N 2)

a² + 9a + 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 9a)=-14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² +9a+20.25)=-14+20.25

Rewrite as perfect squares

(a+4.5)²=6.25--------> (a+4.5)=(+/-)√6.25

a1=-4.5+√6.25-----> a1=-2

a2=-4.5-√6.25-----> a2=-7

the solution problem N 2 is the pair {-2,-7}

N 3)

a² + 3a − 10 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 3a)=10

Complete the square Remember to balance the equation by adding the same constants to each side

(a² + 3a+2.25)=10+2.25

Rewrite as perfect squares

(a+1.5)²=12.25------> (a+1.5)=(+/-)√12.25

a1=-1.5+√12.25-----> a1=2

a2=-1.5-√12.25-----> a2=-5

the solution problem N 3 is the pair {2, -5}

N 4)

a² + 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² + 5a) =14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² + 5a+6.25) =14+6.25

Rewrite as perfect squares

(a+2.5)² =20.25-------> (a+2.5)=(+/-)√20.25

a1=-2.5+√20.25-----> a1=2

a2=-2.5-√20.25-----> a2=-7

the solution problem N 4 is the pair {2, -7}

N 5)

a² − 5a − 14 = 0

Group terms that contain the same variable, and move the constant to the opposite side of the equation

(a² − 5a)=14

Complete the square Remember to balance the equation by adding the same constants to each side

(a² − 5a+6.25)=14+6.25

Rewrite as perfect squares

(a-2.5)²=2025--------> (a-2.5)=(+/-)√20.25

a1=2.5+√20.25-----> a1=7

a2=2.5-√20.25-----> a2=-2

the solution problem N 5 is the pair {7, -2}

3 0

3 years ago

Read 2 more answers

What is 6/4 simplified

Rashid [163]

Since this is an improper fraction, you simplify it into a mixed number.
4 goes into 6 1 time. 2 left left over, resulting in 1 2/4. Simplify that into
1 1/2

6 0

3 years ago

Read 2 more answers

Abigail mixes 2/3 pounds of walnuts with 3/5 pound of dried fruit. To create more of the same mixture, how many pounds of walnut

nignag [31]

1 1/9

To figure out how much walnuts to a pound of dried fruit you’d need to do proportions. So we cross multiply:

2/3 = X
—————- —————-
3/5 = 1

You multiply diagnols 2/3 x 1 = 2/3
3/5 times x is 3/5x.

2/3 = 3/5x. Isolate the variable. Divide 3/5 on both sides cancel out 3/5. 2/3 divide by 3/5 is 2/3 x 5/3 which is 10/9 which equals 1 1/9.

So for 1 lb of dried fruit you need 1 1/9 lb of walnuts to maintain the same mixture

7 0

3 years ago