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2 years ago

A rectangle has a perimeter of 16p centimeters. It has a width of 2p centimeters. Find the length of the rectangle in terms of p

2 answers:

6 0

If the width is 2p then the width of both sides is 4p. Subtract that from the total perimeter and you get 16p-4p= 12p. Divide that by two because there are 2 side lengths. So, one side length is 6p.

9966 [12]2 years ago

5 0

In a rectangle, we know that opposite sides are congruent (the same size). So, if you add the width of one side and the width of the other, you get 4. Then, you would subtract 4 from 16, which is 12. Next, divide 12 by 2 to get 6, the other 2 congruent sides of a rectangle. As a result, the length of the rectangle is 6 centimeters.

Work: w = width. width = 2
16 - 2(w) = l
2

16 - 2(2) = l
2

16 - 4 = 1
2

12 = l
 2

6 = l

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A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

yanalaym [24]

Answer:

Step-by-step explanation:

A recipe uses 214 cups of flour for a batch of cookies. Henry makes 10 batches of cookies for a bake sale.

A model shows a total of c cups divided into 10 sections, each labeled 2 and 1 fourth.

Part A

Which equation models the total number of cups of flour, c, Henry needs?

c+214=10

214×c=10

10+c=214

214×10=c

Part B

How many cups of flour does Henry need?

2014cups

2212cups

2434cups

2512cups

Part C

Estimate how much flour Henry would need to make 15 batches of cookies. Explain.

I would round 214 to 2, so Henry would need about 30 cups of flour.

I would round 214 to 3, so Henry would need about 45 cups of flour.

I would round 214 to 1, so Henry would need about 15 cups of flour.

I would round 214 to 234, so Henry would need about 30 cups of flour.

8 0

3 years ago

Sunspots have been observed for many centuries. Records of sunspots from ancient Persian and Chinese astronomers go back thousan

Lunna [17]

Answer:

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41

Alternate Hypothesis, $H_A$ : $\mu$ > 41

(b) The value of z test statistics is 1.08.

(c) We conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

Step-by-step explanation:

We are given that in a random sample of 40 such periods from Spanish colonial times, the sample mean is x¯ = 47.0. Previous studies of sunspot activity during this period indicate that σ = 35.

It is thought that for thousands of years, the mean number of sunspots per 4-week period was about µ = 41.

Let $\mu$ = mean sunspot activity during the Spanish colonial period.

(a) Null Hypothesis, $H_0$ : $\mu$ $\leq$ 41 {means that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41}

Alternate Hypothesis, $H_A$ : $\mu$ > 41 {means that the mean sunspot activity during the Spanish colonial period was higher than 41}

The test statistics that would be used here One-sample z test statistics as we know about the population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean = 47

σ = population standard deviation = 35

n = sample of periods from Spanish colonial times = 40

So, the test statistics = $\frac{47-41}{\frac{35}{\sqrt{40} } }$

= 1.08

(b) The value of z test statistics is 1.08.

(c) Now, the P-value of the test statistics is given by;

P-value = P(Z > 1.08) = 1 - P(Z < 1.08)

= 1 - 0.8599 = 0.1401

Since, the P-value of the test statistics is higher than the level of significance as 0.1401 > 0.05, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean sunspot activity during the Spanish colonial period was lesser than or equal to 41.

8 0

3 years ago

Here is another problem that can also be solved by working backwards.

g100num [7]

According to my brain, Maddy picked 6 cucumbers.

5 0

3 years ago

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The discounted price of a book is 85% of the original price. This is a savings of $3. A sales tax of 8% will be added to the dis

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I think the sales tax is $0.28 cents