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REY [17]
3 years ago
10

A rectangle has a perimeter of 16p centimeters. It has a width of 2p centimeters. Find the length of the rectangle in terms of p

Mathematics
2 answers:
DIA [1.3K]3 years ago
6 0
If the width is 2p then the width of both sides is 4p. Subtract that from the total perimeter and you get 16p-4p= 12p. Divide that by two because there are 2 side lengths. So, one side length is 6p.
9966 [12]3 years ago
5 0
In a rectangle, we know that opposite sides are congruent (the same size). So, if you add the width of one side and the width of the other, you get 4. Then, you would subtract 4 from 16, which is 12. Next, divide 12 by 2 to get 6, the other 2 congruent sides of a rectangle. As a result, the length of the rectangle is 6 centimeters. 

Work:                                        w = width. width = 2
 <u>16 - 2(w)</u> = l
       2
<u>
</u><u>16 - 2(2)</u> = l
       2
<u>
</u><u>16 - 4</u> = 1
      2

<u>12</u> = l
<u />  2

6 = l


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Step-by-step explanation:

If the parabola has the form

y = a(x - h)^2 + k (vertex form)

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y = \dfrac{1}{6}(x - 8)^2 + 6

is located at the point (8, 6).

To find the length of the parabola's latus rectum, we need to find its focal length <em>f</em>. Luckily, since our equation is in vertex form, we can easily find from the focus (or focal point) coordinate, which is

\text{focus} = (h, k +\frac{1}{4a})

where \frac{1}{4a} is called the focal length or distance of the focus from the vertex. So from our equation, we can see that the focal length <em>f</em> is

f = \dfrac{1}{4(\frac{1}{6})} = \dfrac{3}{2}

By definition, the length of the latus rectum is four times the focal length so therefore, its value is

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5 0
3 years ago
A radioactive substance has a continuous decay rate of 0.056 per minute. How many grams of a 120 gram sample will remain radioac
sammy [17]

Answer:

The mass of the radioactive sample after 40 minutes is 12.8 g.

Step-by-step explanation:

The mass of the sample can be found by using the exponential decay equation:

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Where:

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t = 40 min

λ: is the decay constant =  0.056 min⁻¹

Hence, the mass of the sample after 40 min is:

N_{t} = N_{0}e^{-\lambda t} = 120g*e^{-0.056min^{-1}*40 min} = 12.8 g

     

Therefore, the mass of the radioactive sample after 40 minutes is 12.8 g.

I hope it helps you!

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