PLS HEL P ASAP NOT THAT HARD!! CONVERT TO ENTIRE RADICAL FORM

lidiya [134]

9514 1404 393

Answer:

A. {1, 7, 11}

Step-by-step explanation:

The constant in the equation is 1, so that is the value when x=0. No answer choice can be correct unless it includes the value 1. The only viable choice is A.

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If you want to go to the trouble to evaluate the expression for the different values of x, you can. It often works well to rewrite the expression to "Horner form":

(2x -1)x +1

For x = -2, this is (2(-2) -1)(-2) +1 = (-5)(-2) +1 = 11

For x = 0, this is 1

For x = 2, this is (2(2) -1)(2) +1 = (3)(2) +1 = 7

So, the range for the given domain is {1, 7, 11} . . . . . matches choice A

3 0

3 years ago

1/2 sq. unit 1/2 sq. unit 1 sq. unit 1/2 sq. unit 1/2 sq. unit What is the area of the entire rectangle in square units? Explain

neonofarm [45]

Answer:

3 sq. units

Step-by-step explanation:

<u>Entire area is the sum of areas of sections:</u>

A = 1/2 + 1/2 + 1 + 1/2 + 1/2 =
1+ 4*1/2 =
1 + 2 =
3 sq. units

4 0

3 years ago

Use cylindrical coordinates. find the volume of the solid that lies within both the cylinder x2 y2 = 9 and the sphere x2 y2 z2 =

marissa [1.9K]

In Cartesian coordinates, the region is given by $-3\le x\le3$ , $-\sqrt{9-x^2}\le y\le\sqrt{9-x^2}$ , and $-\sqrt{16-x^2-y^2}\le z\le\sqrt{16-x^2-y^2}$ . Converting to cylindrical coordinates, using

$\begin{cases}\mathbf x(r,\theta,\zeta)=r\cos\theta\\\mathbf y(r,\theta,\zeta)=r\sin\theta\\\mathbf z(r,\theta,\zeta)=\zeta\end{cases}$

we get a Jacobian determinant of $r$ , and the region is given in cylindrical coordinates by $0\le\theta\le2\pi$ , $0\le r\le3$ , and $-\sqrt{16-r^2}\le z\le\sqrt{16-r^2}$ .

The volume is then

$\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\int_{z=-\sqrt{16-r^2}}^{z=\sqrt{16-r^2}}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta=\dfrac{4(64-7\sqrt7)\pi}3$