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Delvig [45]
3 years ago
12

a brass spring weighs .83 Newtons while it is suspended in the air. next you immerse the ring in a container of light corn syrup

. the ring appears to weigh .71 Newtons. what is the buoyant force acting on in the ring of light corn syrup?
Physics
1 answer:
jasenka [17]3 years ago
7 0

The force of gravity on the object is the same all the time ... doesn't matter
whether it's in the air, in a box, or in corn syrup.

So when it's in corn syrup, the <u>difference</u> must be the buoyant force.

  0.83N - 0.71N = <em>0.12 Newton</em>

I'm sorry, but I just have to say how disappointed I am that you couldn't
get through this one on your own.


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Two satellites are orbiting earth at different altitudes. Which satellite orbits at a higher speed v around earth?
aniked [119]

Answer:

Low satellite has high orbital velocity

Explanation:

let v be the orbital speed of the satellite orbiting at a height h is given by

v=\sqrt{\frac{GM}{R+h}}

where, M be the mass of planet, r be the radius of planet and h be the height of planet from the surface of planet.

here we observe that more be the height lesser be the orbital velocity.

So, a satellite which is at low height has high orbital velocity.

3 0
4 years ago
It takes a student 12.0 minutes to get home from school while riding their bike at 6.7 m/s.
givi [52]

Answer: 289.44km

Explanation:

4 0
4 years ago
While tuning a string to the note C at 523 Hz, a piano tuner hears 2.00 beats/s between a reference oscillator and the string.
lara31 [8.8K]

Answer:

a)the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b) 526hz

c)0.989 or a 1.14% decrease in tension

Explanation:

a) While tuning a string at 523 Hz,piano tuner hears 2.00 beats/s between a reference oscillator and the string.

The possible frequencies of the string can be calculated by

fl=f' - B

where

fl= lower limit of the possible frequency

f'= frequency of the string

B= beat heard by the tuner

fl= 523hz + Or - (2beats/secs * 1hz/1beat per sc)

fl= 521hz or 525hz

So the possible frequencies are 521hz ,522hz, 523, 524hz,525hz

b)fl=f' - B

523hz= f' - 3

f'= 523 + 3= 526hz

c) The tension is directly proportional to the square of the frequencies

T1/T2 =f1^2/f2^2

523^2 / 526^2 = 0.989 or a 1.14% decrease in tensio

6 0
3 years ago
At 20°C the vapor pressure of dry ice is 56.5 atm. If 10g of dry ice (solid CO2) is placed in an evacuated 0.25 L chamber at a c
jonny [76]

Answer:

Pressure of the gas is greater than the vapor pressure, therefore all the solid will not sublime.

Explanation:

To solve this problem we use ideal gas equation.

PV =nRT

If Presure of the gas (P) is greater than vapor pressure (56.5 atm), all the solid will not sublime. But If P < 56.5 atm, all of it will sublime.

where;

P is pressure of the gas in atm

V is volume of gas in Litre

T is absolute temperature of the gas in Kelvin

n is number of gas moles

R is ideal gas constant or Boltzmann constant = 0.082057 L atm K⁻¹ mol⁻¹

Given T = 20 °C  = 273 + 20 = 293K

Volume = 0.25L

n = Reacting mas (m)/Molar mass(M)

Molar mass of CO₂ = 12 + (16X2) = 12+32 = 44g/mol

Reacting mass = 10g

n = m/M ⇒ 10/44

n = 0.2273

PV =nRT ⇒ P = nRT/V

P = (0.2273X0.082057 X293)/0.25

P = 21.8596 atm

Therefore, since Pressure of the gas is greater than the vapor pressure, all the solid will not sublime.

5 0
4 years ago
A circular coil has a 8.79 cm radius and consists of 42.0 closely wound turns of wire. An externally produced magnetic field of
OverLord2011 [107]

Answer: The magnetic flux is 3.4 × 10^-3 Wb

Explanation: Please see the attachments below

8 0
3 years ago
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