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Delvig [45]
3 years ago
12

a brass spring weighs .83 Newtons while it is suspended in the air. next you immerse the ring in a container of light corn syrup

. the ring appears to weigh .71 Newtons. what is the buoyant force acting on in the ring of light corn syrup?
Physics
1 answer:
jasenka [17]3 years ago
7 0

The force of gravity on the object is the same all the time ... doesn't matter
whether it's in the air, in a box, or in corn syrup.

So when it's in corn syrup, the <u>difference</u> must be the buoyant force.

  0.83N - 0.71N = <em>0.12 Newton</em>

I'm sorry, but I just have to say how disappointed I am that you couldn't
get through this one on your own.


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I need both parts please (a) Given a material with an attenuation coefficient (a) of 0.6/cm, what is the intensity of a beam (wi
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Answer:

<h3>a.</h3>
  • After it has traveled through 1 cm : I(1 \ cm) = 0.5488 I_0
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<h3>b.</h3>
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<h2>a.</h2>

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I(1 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 1 cm}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = I_0 e^{- 0.6}

I(1 \ cm) = 0.5488 \ I_0

After travelling 2 cm:

I(2 \ cm) = I_0 e^{- 0.6 \frac{1}{cm} \ 2 cm}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = I_0 e^{- 1.2}

I(2 \ cm) = 0.3012 \ I_0

<h2>b</h2>

The optical density od is given by:

od(x) = - log_{10} ( \frac{I(x)}{I_0} ).

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od( 1\ cm) = - log_{10} ( \frac{0.5488 \ I_0}{I_0} )

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od( 2\ cm) = - log_{10} ( \frac{0.3012 \ I_0}{I_0} )

od( 2\ cm) = - log_{10} ( 0.3012 )

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od( 2\ cm) =  0.5211

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