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Alborosie
4 years ago
15

Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double sli

ts 0.500 mm apart illuminated by 500-nm light.
Physics
1 answer:
xeze [42]4 years ago
3 0

Answer:

1.25cm

Explanation:

Using

Minimum, as dsinစ = (m+1/2) lambda

Third dark fringe m= 2

dsinစ = (2+1/2)lambda

d(y/L)= (5/2) lambda

Y= 5/2* lambda *L/d

So substituting

=[ (500E-9m)(5m)/0.5E-3] 5/2

=0.0125m

= 1.25cm

Explanation:

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Which water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B prot
sergiy2304 [10]

Answer:

10 cm

Explanation:

water depth had the biggest difference in survival rates for embryos with UV-B protection versus embryos without UV-B protection is 10 cm . the bar graph attached in the shows that the lengths of yellow and brown bars differ the most at 10 cm.

Hence,The biggest difference between the survival rates of UV-B protected and unprotected can be seen at the depth of 10 cm.

6 0
3 years ago
A 94.0 N grocery cart is pushed 17.6 m along an aisle by a shopper who exerts a constant horizontal force of 42.6 N. The acceler
Vadim26 [7]

Answer:

vf = 12.51 m/s

Explanation:

Newton's second law to the grocery cart:

∑F = m*a Formula (1)

∑F : algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration  (m/s²)

We define the x-axis in the direction parallel to the movement of the grocery cart  and the y-axis in the direction perpendicular to it.

Forces acting on the grocery cart

W: Weight of the block : In vertical direction  downward

N : Normal force : In vertical direction  upward

F : horizontal force

Calculated of the mas of the grocery cart (m)

W = m*g

m = W/g

W = 94.0 N  , g = 9.81 m/s²

m = 94/9.81

m = 9.58 Kg

Calculated of the acceleration of the grocery cart (a)

∑F = m*a

F = m*a

42.6 = (9.58)*a

a = (42.6) / (9.58)

a = 4.45 m/s²

Kinematics Equation of the grocery cart

Because the grocery cart moves with uniformly accelerated movement we apply the following formula to calculate its final speed :

vf²=v₀²+2*a*d Formula (2)

Where:  

d:displacement  (m)

v₀: initial speed  (m/s)

vf: final speed   (m/s)

a: acceleration (m/s²)

Data:

v₀ = 0

a = 4.45 m/s²

d = 17.6 m

We replace data in the formula (2) :

vf²=v₀²+2*a*d

vf² = 0+2*(4.45)*(17.6)

vf² = 156.64

v_{f} = \sqrt{156.64}

vf = 12.51 m/s

7 0
4 years ago
How does an atmosphere change the temperature of a planet?
jolli1 [7]
The existence of atmosphere increases the average planetary temperature by more than 15°C, due to the greenhouse effect of some atmospheric compounds. The most important of them are water vapour (H2O), ozone (O3), carbon dioxide (CO2), and methane (CH4).
6 0
3 years ago
Read 2 more answers
A pendulum of length L = 1 m is released from an initial angle of 15° . After 1000 s, its amplitude is reduced to 2.5º. What is
jonny [76]

Answer:

The value of the time constant is 558.11 sec.

Explanation:

Given that,

Pendulum length = 1 m

Initial angle = 15°

Time = 1000 s

Reduced amplitude = 2.5°

We need to calculate the value of the time constant

Using formula of damping oscillation

\theta=\theta_{0}e^{\dfrac{t}{\tau}}

Where, \theta =amplitude

\theta_{0} =amplitude at t = 0

Put the value into the formula

2.5=15e^{\dfrac{-1000}{\tau}}

\dfrac{1}{6}=e^{\dfrac{-1000}{\tau}}

ln\dfrac{1}{6}=\dfrac{-1000}{\tau}

\tau=\dfrac{1000}{-ln\dfrac{1}{6}}

\tau=558.11\ sec

Hence, The value of the time constant is 558.11 sec.

6 0
3 years ago
Where are elements with few valence electrons found on the periodic table
Nimfa-mama [501]

Answer:

Valence electrons are the electrons present in the outermost shell of an atom. You can easily determine the number of valence electrons an atom can have by looking at its Group in the periodic table.

Explanation:

8 0
3 years ago
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