Answer:
see solution below
Explanation:
The given resistors are connected in series.
Equivalent resistance in series = 30 + 55 + 15
Equivalent resistance in series Rt = 100 ohms
Since the potential difference in the circuit = 36V
Get the current in the circuit first
I = V/Rt
I = 36/100
I = 0.36A
Get the voltage across 30ohms resistor;
V30 = 0.36 * 30
V30 = 10.8volts
Hence the voltage across the 30ohms resistor is 10.8volts
Get the voltage across 55ohms resistor;
V55 = 0.36 * 55
V55 = 19.8volts
Hence the voltage across the 55ohms resistor is 19.8volts
Get the voltage across 15ohms resistor;
V15 = 0.36 * 15
V15 = 5.4volts
Hence the voltage across the 15ohms resistor is 5.4volts
Answer:
Because the light reflects multiple times until it gets to the Cassegrain focus.
Explanation:
The Cassegrain design can be seen in a reflecting telescope. In this type of design the light is collected by a concave mirror, and then intercepted by a secondary convex mirror, and sends it down to a central opening in the primary mirror (concave mirror), in which a detector is placed (Cassegrain focus)
Since, the light is reflected many times due to Cassegrain design, that leads to shorter telescopes.
Answer:
0.75 A
Explanation:
An electric current is a flow of charged particles.
A current is defined through its intensity, which is given by:

where
I is the current intensity
q is the charge passing through a given point in the circuit
t is the time it takes for the charge q to pass that point in the circuit
In this problem, we have:
q = 45 C is the charge passing through the point in the circuit
is the time elapsed
Therefore, the current intensity is:

You are working for a manufacturing company, which is mathematically given as
<h3>What is the
value of m that will place the
movable bead in equilibrium at x-a a ....?</h3>
a)
Generally, the equation for the force of equilibrium is mathematically given as
F=2fcos\theta
Therefore


b)
By force equilibrium

Therefore


c)

x^2+a^2=(14/3)^{2/3}x^2
x=a/1.338
x=0.747a
d)
By force equilibrium


Read more about electric fields
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