Question

Estimate the distance (in cm) between the central bright region and the third dark fringe on a screen 5.00 m from two double slits 0.500 mm apart illuminated by 500-nm light.

Answer 1

Answer:

1.25cm

Explanation:

Using

Minimum, as dsinစ = (m+1/2) lambda

Third dark fringe m= 2

dsinစ = (2+1/2)lambda

d(y/L)= (5/2) lambda

Y= 5/2* lambda *L/d

So substituting

=[ (500E-9m)(5m)/0.5E-3] 5/2

=0.0125m

= 1.25cm

Explanation: