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spin [16.1K]
4 years ago
7

It takes a student 12.0 minutes to get home from school while riding their bike at 6.7 m/s.

Physics
1 answer:
givi [52]4 years ago
4 0

Answer: 289.44km

Explanation:

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The transfer of thermal energy via electromagnetic waves is know as what
katrin2010 [14]

Answer:

Radiation

Explanation:

7 0
3 years ago
A california condor is sitting on the top branch of a redwood tree and has a GPE of 12,100 J. If the condor has a mass of 8kg, w
DanielleElmas [232]

Answer:

william h. seward secured the purchase of alaska from:

Explanation:

3 0
3 years ago
If a 4500 kg car is traveling with an acceleration of 35.2 m/s/s, what is the force acting on it?
Elena L [17]

Answer:

<h2>158,400 J</h2>

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question we have

force = 4500 × 35.2 = 158400

We have the final answer as

<h3>158,400 J</h3>

Hope this helps you

3 0
2 years ago
An instrument is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/
Katen [24]
<h2>Answer: 12 s</h2>

Explanation:

The situation described here is parabolic movement. However, as we are told <u>the instrument is thrown upward</u> from the surface, we will only use the equations related to the Y axis.

In this sense, the main movement equation in the Y axis is:

y-y_{o}=V_{o}.t-\frac{1}{2}g.t^{2}    (1)

Where:

y  is the instrument's final position  

y_{o}=0  is the instrument's initial position

V_{o}=15m/s is the instrument's initial velocity

t is the time the parabolic movement lasts

g=2.5\frac{m}{s^{2}}  is the acceleration due to gravity at the surface of planet X.

As we know y_{o}=0  and y=0 when the object hits the ground, equation (1) is rewritten as:

0=V_{o}.t-\frac{1}{2}g.t^{2}    (2)

Finding t:

0=t(V_{o}-\frac{1}{2}g.t^{2})   (3)

t=\frac{2V_{o}}{g}   (4)

t=\frac{2(15m/s)}{2.5\frac{m}{s^{2}}}   (5)

Finally:

t=12s

3 0
4 years ago
Need help... 44 points!!!!
vladimir1956 [14]

As per conditions described here we know that all force arrow are not of equal length

So all forces are not same in magnitude

Here applied force on right direction is more in magnitude then the friction force on left

So it will have net unbalanced force towards right due to which it will move towards right direction or in the direction of net unbalanced force

While in the upward and downward direction the forces are balanced and hence the box will not move in that direction

So normal force will be balanced by gravitational force

So here answer will be

The forces acting on the box are <u>UNBALANCED</u> .

The box will move to the <u>RIGHT</u> .

7 0
4 years ago
Read 2 more answers
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