The answer is B.
172.0 in.²
Answer:
03%
Step-by-step explanation:
In this situation Mickey should have drew first 7 cards that are not diamond and then on the 8th attempt she should draw an ace.
Let A be the event of drawing 7 cards which are not diamond and B the event of drawing an ace card. therefore required probability is P(A∩B)=P(A)*P(B)
Now, there are 13 diamonds and 39 other cards. Hence,
P(A)=(
)⁷=0.1335
After drawing 7 non-diamond cards, the 8th card must be a diamond.Hence,
P(B)=
=0.25
Hence, P(A∩B)=P(A)*P(B)=0.1335*0.25=0.033(approximately 0.03,i.e. 3%)
Therefore probability that Mickey will draw her first diamond on the 8th
attempt is 3%
The given equation is:
0 + 7y + 2 = 7y + 2
This equation is showing that addition of 0 leaves the expression unchanged. 0 is known as the Additive Identity this means if we add or subtract 0 from any expression, number or equation the result won't be changed.
Therefore, the equation satisfied the property of Additive Identity of Real Numbers.
Answer:
<h2><em>
2ft by 2ft by 1 ft</em></h2>
Step-by-step explanation:
Total surface of the cardboard box is expressed as S = 2LW + 2WH + 2LH where L is the length of the box, W is the width and H is the height of the box. Since the cardboard box is without a lid, then the total surface area will be expressed as;
S = lw+2wh+2lh ... 1
Given the volume V = lwh = 4ft³ ... 2
From equation 2;
h = 4/lw
Substituting into r[equation 1;
S = lw + 2w(4/lw)+ 2l(4/lw)
S = lw+8/l+8/w
Differentiating the resulting equation with respect to w and l will give;
dS/dw = l + (-8w⁻²)
dS/dw = l - 8/w²
Similarly,
dS/dl = w + (-8l⁻²)
dS/dw = w - 8/l²
At turning point, ds/dw = 0 and ds/dl = 0
l - 8/w² = 0 and w - 8/l² = 0
l = 8/w² and w =8/l²
l = 8/(8/l² )²
l = 8/(64/I⁴)
l = 8*l⁴/64
l = l⁴/8
8l = l⁴
l³ = 8
l = ∛8
l = 2
Hence the length of the box is 2 feet
Substituting l = 2 into the function l = 8/w² to get the eidth w
2 = 8/w²
1 = 4/w²
w² = 4
w = 2 ft
width of the cardboard is 2 ft
Since Volume = lwh
4 = 2(2)h
4 = 4h
h = 1 ft
Height of the cardboard is 1 ft
<em>The dimensions of the box that requires the least amount of cardboard is 2ft by 2ft by 1 ft</em>
First you start off by setting up a Subtraction problem there anything common denominators of 7/8 and two over three verse 7/8 you should get 21/24 invert to over three you should get 16/24 then you would subtract those two anyway to get 5/24 I hope that was helpful get it