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Anastasy [175]
3 years ago
7

the distance covered by a car depends on how fast the car was going and on how long it has travelled?​

Mathematics
1 answer:
Licemer1 [7]3 years ago
4 0

Answer:

Yes it does

Step-by-step explanation:

Distance is equal to rate multiplied by time and the rate is how fast the car is going and how long is the time so yes it will be equal to distance.

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Answer:

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Step-by-step explanation:

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antiseptic1488 [7]

Answer:

\sf -11+7\sqrt{2}

Step-by-step explanation:

Given expression:

\sf \dfrac{3-\sqrt{32}}{1+\sqrt{2} }

Rewrite 32 as 16 · 2:

\sf \implies \dfrac{3-\sqrt{16 \cdot 2}}{1+\sqrt{2} }

Apply radical rule \sf \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\sf \implies \dfrac{3-\sqrt{16}\sqrt{2}}{1+\sqrt{2} }

As \sf \sqrt{16}=4:

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Multiply by the conjugate:

\sf \implies \dfrac{3-4\sqrt{2}}{1+\sqrt{2} } \times \dfrac{1-\sqrt{2} }{1-\sqrt{2} }

\sf \implies \dfrac{(3-4\sqrt{2})(1-\sqrt{2})}{(1+\sqrt{2})(1-\sqrt{2})}

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<em />

<em>Hope this helps!!!</em>

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