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3 years ago

the distance covered by a car depends on how fast the car was going and on how long it has travelled?

Mathematics

1 answer:

Licemer1 [7]3 years ago

4 0

Answer:

Yes it does

Step-by-step explanation:

Distance is equal to rate multiplied by time and the rate is how fast the car is going and how long is the time so yes it will be equal to distance.

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How many 2 litre glasses of water are in a 3.6 litre pitcher

Lubov Fominskaja [6]

The answer would be '2'.

7 0

3 years ago

In a circus performance, a monkey is strapped to a sled and both are given an initial speed of 3.0 m/s up a 22.0° inclined track

Aloiza [94]

Answer:

Approximately $0.31\; \rm m$ , assuming that $g = 9.81\; \rm N \cdot kg^{-1}$ .

Step-by-step explanation:

Initial kinetic energy of the sled and its passenger:

$\begin{aligned}\text{KE} &= \frac{1}{2}\, m \cdot v^{2} \\ &= \frac{1}{2} \times 14\; \rm kg \times (3.0\; \rm m\cdot s^{-1})^{2} \\ &= 63\; \rm J\end{aligned}$ .

Weight of the slide:

$\begin{aligned}W &= m \cdot g \\ &= 14\; \rm kg \times 9.81\; \rm N \cdot kg^{-1} \\ &\approx 137\; \rm N\end{aligned}$ .

Normal force between the sled and the slope:

$\begin{aligned}F_{\rm N} &= W\cdot \cos(22^{\circ}) \\ &\approx 137\; \rm N \times \cos(22^{\circ}) \\ &\approx 127\; \rm N\end{aligned}$ .

Calculate the kinetic friction between the sled and the slope:

$\begin{aligned} f &= \mu_{k} \cdot F_{\rm N} \\ &\approx 0.20\times 127\; \rm N \\ &\approx 25.5\; \rm N\end{aligned}$ .

Assume that the sled and its passenger has reached a height of $h$ meters relative to the base of the slope.

Gain in gravitational potential energy:

$\begin{aligned}\text{GPE} &= m \cdot g \cdot (h\; {\rm m}) \\ &\approx 14\; {\rm kg} \times 9.81\; {\rm N \cdot kg^{-1}} \times h\; {\rm m} \\ & \approx (137\, h)\; {\rm J} \end{aligned}$ .

Distance travelled along the slope:

$\begin{aligned}x &= \frac{h}{\sin(22^{\circ})} \\ &\approx \frac{h\; \rm m}{0.375}\end{aligned}$ .

The energy lost to friction (same as the opposite of the amount of work that friction did on this sled) would be:

$\begin{aligned} & - (-x)\, f \\ = \; & x \cdot f \\ \approx \; & \frac{h\; {\rm m}}{0.375}\times 25.5\; {\rm N} \\ \approx\; & (68.1\, h)\; {\rm J}\end{aligned}$ .

In other words, the sled and its passenger would have lost (approximately) $((137 + 68.1)\, h)\; {\rm J}$ of energy when it is at a height of $h\; {\rm m}$ .

The initial amount of energy that the sled and its passenger possessed was $\text{KE} = 63\; {\rm J}$ . All that much energy would have been converted when the sled is at its maximum height. Therefore, when $h\; {\rm m}$ is the maximum height of the sled, the following equation would hold.

$((137 + 68.1)\, h)\; {\rm J} = 63\; {\rm J}$ .

Solve for $h$ :

$(137 + 68.1)\, h = 63$ .

$\begin{aligned} h &= \frac{63}{137 + 68.1} \approx 0.31\; \rm m\end{aligned}$ .

Therefore, the maximum height that this sled would reach would be approximately $0.31\; \rm m$ .

7 0

2 years ago

PLEASE HELP ME

yuradex [85]

The answer is C because it’s going back 5 times meaning it’s -5

8 0

2 years ago

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A Japanese bullet train travels 558 miles per 3 hours A. What is the rate B. How far does the train travel in 1 hour WHO EVER A

Delicious77 [7]

Answer:

Step-by-step explanation:

Remark

The rate is going to be the same as the distance travelled in 1 hour. The units will be different.

Formula

d = r * t

Givens

d = 558 miles

t = 3 hours

Problem A

r = d / t

r = 558/ 3 = 186 miles / hr

Problem B

Givens

r = 186 miles / hour

t = 1 hour

d = ?

Solution

d = 186 mi/hr * 1 hr

d = 186 miles

This looks really trivial, but it's not. You have to learn to see the difference between a number and its units. It's not very often that the numbers will be the same, but if the units differ, then it is an entirely different question.

7 0

2 years ago

1 and 2 plz help me im nice:)

jek_recluse [69]

Answer:

1. 13

2. 28

Step-by-step explanation:

hope this helps

7 0

3 years ago

Read 2 more answers

the distance covered by a car depends on how fast the car was going and on how long it has travelled?​

the distance covered by a car depends on how fast the car was going and on how long it has travelled?