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Reika [66]
3 years ago
14

What is 3/8 + 1/8?? Please help its for a test

Mathematics
2 answers:
devlian [24]3 years ago
7 0

Answer:

4/8

Step-by-step explanation:

The denominators are already the same so you just go ahead and add the numerators

3+1 = 4

4/8

Grace [21]3 years ago
3 0

Answer:

1/2 is the answer

Step-by-step explanation:

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1²+3²+4²+.......+(2n-2)²= ⅓n(2n-1)(2n+1)
sergiy2304 [10]
                       1² + 3² + 4² + 4(n - 1)² = ¹/₃n(2n - 1)(2n + 1)
                       1² + 3² + 4² + (2n - 2)² = ¹/₃n(2n - 1)(2n + 1)
              1 + 9 + 16 + (2n - 2)(2n - 2) = ¹/₃n(2n(2n + 1) - 1(2n + 1))
  10 + 16 + (2n(2n - 2) - 2(2n - 2)) = ¹/₃n(2n(2n) + 2n(1) - 1(2n) - 1(1)    16 + (2n(2n) - 2n(2) - 2(2n) + 2(2)) = ¹/₃n(4n² + 2n - 2n - 1)
                     26 + (4n² - 4n - 4n + 4) = ¹/₃n(4n² - 1)
                            26 + (4n² - 8n + 4) = ¹/₃n(4n² - 1)
                              26 + 4n² - 8n + 4 = ¹/₃n(4n²) - ¹/₃n(1)
                              4n² - 8n + 4 + 26 = 1¹/₃n³ - ¹/₃n
                                    4n² - 8n + 30 = 1¹/₃n³ - ¹/₃n
                                          + ¹/₃n                     + ¹/₃n
                                 4n² - 7²/₃n + 30 = 1¹/₃n³
                   -1¹/₃n³ + 4n² - 7²/₃n + 30 = 0
             -3(-1¹/₃n³ + 4n² - 7²/₃n + 30) = -3(0)
-3(-1¹/₃n³) - 3(4n²) - 3(-7²/₃n) - 3(30) = 0
                        4n³ - 12n² + 23n - 90 = 0
8 0
4 years ago
A tennis tournament has 2n contestants. We want to pair them up for the first round of singles matches. Show that the number of
ddd [48]

There are

\dbinom{2n}2 = \dfrac{(2n)!}{2! (2n-2)!}

ways of pairing up any 2 members from the pool of 2n contestants. Note that

(2n)! = 1\times2\times3\times4\times\cdots\times(2n-2)\times(2n-1)\times(2n) = (2n-2)! \times(2n-1) \times(2n)

so that

\dbinom{2n}2 = \dfrac{(2n)\times(2n-1)\times(2n-2)!}{2! (2n-2)!} = \boxed{n(2n-1)}

4 0
2 years ago
What is the first step in solving In(x - 1) = In6 - Inx for x?
kobusy [5.1K]

Answer:

x=3

Step-by-step explanation:

In(x-1) = In(6) - In(x)

In(x-1) + In(x) = In(6)

In((x-1)x) = In(6)

In(x^2-x) = In(6)

x^2-x=6

x^2-x-6=0

x^2+2x-3x-6=0

x(x+2)-3(x+2)=0

(x-3)(x+2)=0

x=3 because x=-2 need to be cancel out

8 0
2 years ago
8. On a winter's day, the temperature at 6 P.M.
Ivahew [28]

Answer:5 hours because -2.5*5=-12.5

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Work out the size of an exterior and an interior angle of a regular 16-sided<br>polygon.​
timurjin [86]

Answer:

exterior angle: 22.5°, interior angle: 157.5°

Step-by-step explanation:

the formula for the measure of each Interior Angle in a regular polygon: \frac{180(n-2)}{n}, n = # of sides

=> \frac{180(16 - 2)}{16} = 157.5°

the formula for the measure of each Exterior Angle in a regular polygon: \frac{360}{n}

=> \frac{360}{16} = 22.5°

6 0
3 years ago
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