If the particles in a sample of matter have an orderly arrangement and move only in place, the sample is a
1 answer:
Hi!
The answer would be <u>solid.</u>
<u>Explanation:</u>
There are three essential states of matter:
- Solid
- Liquid
- Gas
In a solid, the particles are seen to be in a strict orderly arrangement, and only show restricted movement about their place.
In a liquid, the particles do not have a particular arrangement, and have a more free movement with respect to solid, and can change their position through the sample.
In a gas, the particles are most widely spaced, and have no defined arrangement. They have the most free movement of the other two states.
<em>See the attached picture for a clearer idea.</em>
Hope this helps!
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The enthalpy of reaction for the combustion of ethane 2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O calculated from the average bond energies of the compounds is -2860 kJ/mol.
The reaction is:
2CH₃CH₃ + 7O₂ → 4CO₂ + 6H₂O (1)
The enthalpy of reaction (1) is given by:
(2)
Where:
r: is for reactants
p: is for products
The bonds of the compounds of reaction (1) are:
- 2CH₃CH₃: 2 moles of 6 C-H bonds + 2 moles of 1 C-C bond
- 7O₂: 7 moles of 1 O=O bond
- 4CO₂: 4 moles of 2 C=O bonds
- 6H₂O: 6 moles of 2 H-O bonds
Hence, the enthalpy of reaction (1) is (eq 2):
Therefore, the enthalpy of reaction for the combustion of ethane is -2860 kJ/mol.
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