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butalik [34]
3 years ago
10

In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.10 atm, how many moles of steam

are in the cooker?

Chemistry
1 answer:
Olenka [21]3 years ago
7 0

Answer: 0.39mol of the steam are in the cooker.

Explanation:Please see attachment for explanation

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An element 'X after reacting with acids liberates hydrogen gas and candisplace lead and mercury from their salt solutions. The m
adell [148]

The element X is Copper.

Explanation :

Reactive metals from 3d transition series like Cu are very reactive because their standard reduction potential values are low.

Hence, when treated with a acid it tends to liberate hydrogen gas.

Also, because of  its low reduction potential value, it can easily displace lead and tin from their salt solutions.

Learn more :

https://brainly.in/question/6679934

5 0
3 years ago
What volume of 15.6M NH4OH is needed to make 500. mL of 3.00M solution?
Mariana [72]

Answer:

V₁  = 96.2 mL

Explanation:

Given data:

Initial volume of NH₄OH required = ?

Initial molarity = 15.6 M

Final molarity = 3.00 M

Final volume = 500.0 mL

Solution:

Formula:

M₁V₁  =  M₂V₂

M₁ = Initial molarity

V₁  =  Initial volume of NH₄OH

M₂ =Final molarity

V₂ = Final volume

Now we will put the values.

15.6 M ×V₁  =  3.00 M×500.0 mL

15.6  M ×V₁  = 1500 M.mL

V₁  = 1500 M.mL /15.6 M

V₁  = 96.2 mL

6 0
3 years ago
Which of the following is the formula for Hypochlorous acid?
Leno4ka [110]

Answer:

HClO

Explanation:

7 0
3 years ago
Which of these is an example of a chemical change?
Elena-2011 [213]

Answer:

D. Burning a peice of wood

Explanation:

Because when you burn wood a chemical reaction happenes between the flames and the wood making the wood into ashes.

Hope this helps you :)

3 0
2 years ago
Which of the following statements is not correct?
velikii [3]
To answer the question above, multiply the given number of moles by the molar masses.

(A)     (0.20 mole) x (32 g / 1 mole) = 6.4 grams O2
(B)     (0.75 mole) x (62 g / 1 mole) = 46.5 grams H2CO3
(C)     (3.42 moles) x (28 g / 1 mole) = 95.7 grams CO
(D)     (4.1 moles) x (29.88 g / 1 mole) = 122.508 g Li2O

The answer to the question above is letter D.
4 0
3 years ago
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