Jack is 2 times as old as Lacy. 5 years ago the sum of their ages was 20. How old are they now?

Which of the following are independent variables?

Lapatulllka [165]

Answer:

i think that it is oil

Step-by-step explanation:

because it does not change

4 0

3 years ago

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I have an easy and quick question. So the picture shows an answered question but how do you know to divide? I just don't underst

11111nata11111 [884]

Answer:

Ok so u know to divide bc u r trying to isolate the variable and that means undoing the function in this case 0.6 is multiplied to p so u do the opposite which is division

tada

Hope this helps :)

Pls give brainliest XD :)

8 0

2 years ago

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Please answer this question, will give brainliest!

Ad libitum [116K]

Answer:

I dont really know the answer.. but ill try; if its wrong I am so sorry;

Step-by-step explanation:

First you must get the area of a circle, which is; A= pi r squared

and all you have to do is fill it in like this;

A= 3.14 x 2.0

^

A= 6.28

5 0

3 years ago

Three fair coins are tossed. If all land "heads," the player wins $10, and if exactly two land heads, the player wins $5. If it

hodyreva [135]

Answer:

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

If three coins land "heads" the player wins $ 10

If two coins land "heads" the player wins $ 5

Cost of playing = $ 4

2. What is the player's expected outcome after four games?

Probability of two coins out of three lands "heads" = 3/8

Probability of three coins out of three lands "heads" = 1/8

Now, let's calculate the player's expected outcome, as follows:

Four games:

Cost = 4 * 4 = $ 16

Worst-case scenario: No wins

Best-case scenario: 4 out of 4 of $ 10 win

Worst-case scenario profit or loss = 0 - 16 = Loss of $ 16

Best-case scenario profit or loss = 40 - 16 = Profit of $ 24

After four games, a player can lose up to $ 16 to win up to $ 26. These are the probabilities for every game:

1/8 or 12.5% of landing three "heads"

3/8 or 37.5% of landing two "heads"

4/8 or 50% of landing no or only one "head".

8 0

2 years ago

In the figure, a square is inside another bigger square.

evablogger [386]

Answer:

Part 1) The length of the diagonal of the outside square is 9.9 units

Part 2) The length of the diagonal of the inside square is 7.1 units

Step-by-step explanation:

step 1

Find the length of the outside square

Let

x -----> the length of the outside square

c ----> the length of the inside square

we know that

$x=a+b=4+3=7\ units$

step 2

Find the length of the inside square

Applying the Pythagoras Theorem

$c^{2}= a^{2}+b^{2}$

substitute

$c^{2}= 4^{2}+3^{2}$

$c^{2}=25$

$c=5\ units$

step 3

Find the length of the diagonal of the outside square

To find the diagonal Apply the Pythagoras Theorem

Let

D -----> the length of the diagonal of the outside square

$D^{2}= x^{2}+x^{2}$

$D^{2}= 7^{2}+7^{2}$

$D^{2}=98$

$D=9.9\ units$

step 4

Find the length of the diagonal of the inside square

To find the diagonal Apply the Pythagoras Theorem

Let

d -----> the length of the diagonal of the inside square

$d^{2}= c^{2}+c^{2}$

$d^{2}= 5^{2}+5^{2}$

$d^{2}=50$

$d=7.1\ units$

7 0

3 years ago

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