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ycow [4]
3 years ago
5

Rose counted her money and found that her 25 coins which were nickels, dimes, and quarters were worth $3.20. the number of dimes

exceeded the number of nickels by 4. how many coins of each kind did she have?
Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
4 0
N = number of nickles 
<span>D = number of dimes = N+4 </span>
<span>Q = number of quarters </span>
<span>= 25-N-D </span>
<span>= 25-N-(N+4) </span>
<span>= 21-(2N) </span>

<span>Add the coins to get $3.20 </span>
<span>(N*$0.05) + (D*$0.10) + (Q*$0.25) = $3.20 </span>
<span>Expressing D and Q in terms of N: </span>
<span>(N*$0.05) + ((N+4)*$0.10) + (21-2N)*$0.25=$3.20 </span>

<span>Solve for N. Then plug N into the equations for D and Q</span>
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