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prisoha [69]
3 years ago
13

The decimal 132.64 written in expanded form is _________?

Mathematics
2 answers:
Westkost [7]3 years ago
8 0
Konichiwa !
the answer is three hundred thirty-two and sixty-four hundredths please for give me if the answer is incorrect i hope it helped you.
have a nice day! 
valentina_108 [34]3 years ago
7 0
Three hundred thirty-two and sixty-four hundreths
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Which is not Equivalent to 3:5 <br> A.30:50<br> B.21:28<br> C:15:28<br> D.9:15
kirza4 [7]

Answer:

B.

Step-by-step explanation:

Since 21 is divided by 3 you might think that it is equivalent but remeber you have to divide by both sides, so if you divide 21 by 7 it works but 28 by seven does not! Hope this helps!

3 0
3 years ago
Which of the following has 14.705 in written form?
Bezzdna [24]

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b

Step-by-step explanation:

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3 years ago
Can anyone show me how to divide 931/7
Inessa [10]
(You go from left to right)
(Dividend is 931, divisor is 7)
Step 1: Look for a number smaller than 9 that is divisible by 7. 7 is the only one which is smaller than 9 and is divisible by 7. Now that you know 7*1=7, you put 1 above 931 (Dividend)
 Step 2: You subtract that number from the number in tens place. And bring the leftover down.
Step 3: You repeat Step 1 and 2 until either you get a remainder of 0 or the remainder in smaller than the divisor (in this case 7)
(Therefore 931/7=133, quotient=133, remainder=0)
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7 0
3 years ago
Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC . What is the leng
Thepotemich [5.8K]

Answer:

Length of side of rhombus is x=\frac{ab}{a+b}  

Step-by-step explanation:

Given Rhombus ADEF is inscribed into a triangle ABC so that they share angle A and the vertex E lies on the side BC. We have to find the length of side of rhombus.

It is also given that AB=a and AC=b

Let side of rhombus is x.

In ΔCEF and ΔCBA

∠CEF=∠CBA        (∵Corresponding angles)

∠CFE=∠CAB        (∵Corresponding angles)

By AA similarity rule, ΔCEF~ΔCBA

∴ their sides are in proportion

\frac{EF}{AB}=\frac{CF}{AC}

⇒ \frac{x}{a}=\frac{b-x}{b}

⇒ xb=ab-ax

⇒ x(a+b)=ab

⇒ x=\frac{ab}{a+b}

Hence, length of side of rhombus is x=\frac{ab}{a+b}  

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3 years ago
Donald weighed 154 pounds. His body fat percentage was 24%. How much of his<br> weight was body fat?
Eduardwww [97]
36.96 with the formula 0.24 * 154 = 36.96
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3 years ago
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