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lianna [129]
3 years ago
6

What is the smallest quantil used in the recipe

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
1/8 teaspoon saffron or ground turmeric
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What are the x-intercepts of 4x^ + 8x - 5
mojhsa [17]
Assuming the exponent is supposed to be "^2" your equation will read:

4x² + 8x - 5

It must set equal to y to be a valid function and the y must be set equal to zero to find x-intercepts.

4x² + 8x - 5 = 0
4x² - 2x + 10x - 5 = 0
2x(2x - 1) + 5(2x - 1) = 0

(2x + 5)(2x - 1) = 0

Set each binomial equal to zero.

2x + 5 = 0
2x = 0 - 5
2x = - 5
Divide both sides by 2
x = - 5/2

2x - 1 = 0
2x = 0 + 1
2x = 1
x = 1/2

Your x-intercepts are x = - 5/2, 1/2 or (- 5/2, 0) and (1/2, 0)
6 0
3 years ago
A science fair poster is a rectangle 36 inches long and 24 inches wide what is the area of the poster in square feet
ella [17]
Well it has to be 3*2 = 6 square feet.  Note: first convert 36 inches to 3 feet and 24 inches to 2 feet.
6 0
3 years ago
Solve 2csc^2x-2cscx-1=0 <br> for 0° ≤ x ≤ 360°
umka21 [38]

Answer:

Step-by-step explanation:

2 csc²x-2 csc x-1=0

or

\frac{2}{sin^2x} -\frac{2}{sin x} -1=0\\multiply~by~sin^2x\\2-2sin~x-sin^2x=0\\sin^2x+2sinx-2=0\\sin ~x=\frac{-2 \pm\sqrt{2^2-4*1*(-2)} }{2*1} \\=\frac{-2 \pm\sqrt{4+8} }{2} \\=\frac{-2 \pm\sqrt{4*3} }{2} \\=\frac{-2 \pm2\sqrt{3} }{2} \\=-1\pm\sqrt{3} \\|sin~x| \le ~1\\so~sin~x=-1+\sqrt{3} \\sin~x=\sqrt{3} -1\\x=sin^{-1}(\sqrt{3} -1) \approx 47.06^\circ,180-47.06\\or~x=47.06^\circ,132.94^\circ

6 0
3 years ago
(-8)^-2 / 3^-4 simplify the expression. Write your answer using only positiv exponents.
spin [16.1K]

Answer:

3^4 / 8^2 or 81/64

Step-by-step explanation:

(-8)^-2 / 3^-4 =

= 3^4 / (-8)^2

= 3^4 / 8^2

= 81/64

4 0
3 years ago
C = ?<br>Be sure to evaluate the square root​
Butoxors [25]

Hope this will help u .

If my ans was helpful, u can follow me.

4 0
3 years ago
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