The true statement about right-angle triangle ABC is that: A. sin(A) = cos(C) and cos(A) = sin(C).
<h3>How to apply basic trigonometry?</h3>
In order to determine the angles, we would apply basic trigonometry. From the diagram of the right-angled triangle shown below, we can deduce the following parameters:
By applying the basic trigonometry functions, we have:
sin(A) = Opp/Hyp = a/c.
sin(C) = Opp/Hyp = c/b.
cos(A) = Adj/Hyp = c/b.
cos(C) = Adj/Hyp = a/c.
From the above, we can logically deduce that sin(A) is equal to cos(C) and cos(A) is equal to sin(C).
Read more on sine trigonometry here: brainly.com/question/20367642
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Answer:
m= -3/2
Step-by-step explanation:
First, we must find the slope of the line given. We are given the equation:
y-2/3x=2
We must get this equation in slope-intercept form: y=mx+b (where m is the slope and b is the y-intercept). In order to do this, we must get y isolated.
2/3x is being subtracted from y. We want to preform the inverse, so we should add 2/3x to both sides.
y-2/3x+2/3x=2+2/3x
y=2+2/3x
Rearrange the terms.
y= 2/3x+2
Now the equation is in slope intercept form. (y=mx+b). 2/3 and x are being multiplied, so we know that the slope is 2/3.
Now, we have to find the perpendicular slope. Perpendicular lines have negative reciprocal slopes.
1. Negative
m=2/3
Negate the slope.
m= -2/3
2. Reciprocal
m= -2/3
Flip the numerator (top number) and denominator (bottom number).
m= -3/2
The perpendicular slope is -3/2
Answer:
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Answer:
1080000
Step-by-step explanation:
