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3 years ago

A bacteria culture initially contains 2500 bacteria and doubles every half hour.

Mathematics

2 answers:

8090 [49]3 years ago

6 0

Answer:

35000

Step-by-step explanation:

I don't know the first one but I do know that in 7 hours it will be 35000

cluponka [151]3 years ago

4 0

Answer:

1. 3333.33

2. 20,480,000

Step-by-step explanation:

1. first term= 2500microganism.

in ten minutes =2500/3=833.33

some organisms do not completely divide.

first term + ten minutes

=2500+833.33= 3333.33 organisms

2. using geometric progression with formula Tn=ar^n-1

r=common ratio= for this question it is 2.

a= first term

therefore, 30 minutes=1st term

so, 7hours =14th term

T14= 2500*2^(14-1)

= 2500*2^13

= 2500*8192

= 20,480,000 micoorganisms

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An angle measures 12° less than three times it’s supplement. Find the measure of the angle

Butoxors [25]

Answer:

132 degrees.

Step-by-step explanation:

Let the supplement be x and the angle be y.

x + y = 180 degrees.

y = (3x - 12) degrees.

x + 3x - 12 = 180

4x = 192

x = 48 degrees

y = 132 degrees

Hope this helped!

6 0

3 years ago

Sorry to be annoying again I just really suck at math and I haven't slept yet

Vesna [10]

Answer:

50.33 mi.

Step-by-step explanation:

GIVEN :-

Coordinates of :-

Home = (0 , 0)
School = (4 , 3)
Pizza place = (-8 , 2)
Movie Theater = (-4 , -6)
Park = (7 , -5)

TO FIND :-

Total distance travelled on Friday & Saturday.

GENERAL FORMULAE TO BE USED IN THIS QUESTION :-

Lets say there are two points A & B on a cartesian plane whose coordinates are (x₁ , y₁) & (x₂ , y₂).

Distance between A & B = $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

SOLUTION :-

According to question ,

On Friday , you -

leave school and go to pizza palace. Distance travelled from school to pizza palace = $\sqrt{(4 -(-8) )^2 + (3 - 2)^2} = \sqrt{(12)^2 + (1)^2} = \sqrt{145}$ ≈ 12.04 mi.
go to movie theater after pizza palace. Distance travelled from pizza palace to movie theater = $\sqrt{[(-4) -(-8)]^2 + (-6 - 2)^2} = \sqrt{(4)^2 + (-8)^2} = \sqrt{80}= 4\sqrt{5}$ ≈ 8.94 mi.
come back to your home after the movies. Distance travelled from theater to home = $\sqrt{[0-(-4)]^2 + (0 - 6)^2} = \sqrt{(4)^2 + (-6)^2} = \sqrt{52} = 2\sqrt{13}$ ≈ 7.21 mi.

⇒ On Friday , total distance travelled = 12.04 + 8.94 + 7.21 = 28.19 mi.

On Saturday , you -

go to park from your home. Distance travelled from home to park = $\sqrt{(7 -0 )^2 + (-5 - 0)^2} = \sqrt{(7)^2 + (-5)^2} = \sqrt{74}$ ≈ 8.6 mi.
go to school after going to park. Distance travelled from park to school = $\sqrt{(4 -7 )^2 + [3 - (-5)]^2} = \sqrt{(-3)^2 + (8)^2} = \sqrt{73}$ ≈ 8.54 mi.
go to home after playing basketball in school. Distance travelled from school to home = $\sqrt{(0 -4 )^2 + (0 - 3)^2} = \sqrt{(-4)^2 + (-3)^2} = \sqrt{25}$ = 5 mi.