In a group of 33 pupils, 1 plays the flute only.
1 answer:
Answer:
0.303
Step-by-step explanation:
The number of students who plays both flute and Piano can be obtained thus :
Let numbwr who plays both =x
Piano only + flute only + both + neither = total
12 + 1 + x + 10 = 33
23 + x = 33
x = 33 - 23
x = 10
Hence, probability that student plays both instrument :
P = required outcome / Total possible outcomes
P(plays both) = 10 / 33 = 0.303
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To solve algebraically, remove a factor of 2 from the second equation and use that expression to substitute for y in the first equation.
10x^2 -(8x^2 +24) = 48
2x^2 = 72
x = ±√(72/2) = ±6
y = 8*36 +24 = 312