Find Lim f(x) as x->0
for
f(x)=5x-8 ......x<0
f(x)=|-4-x|......x ≥ 0
Clearly
f(0)=|-4-0|=|-4|=4 exists.
The left-hand limit, as x-> 0- is f(0-)=5(0)-8=-8
The right hand limit, as x->0+ is f(0+)=|-4-0|=|-4|=4
Since the left and right limits do not both equal f(0), the limit does not exist.
3.0 NOT SURE IF ITS CORRECT
Answer: area for circle is πr² so πr² =28.26 and we can sub 3.14 as pi
3.14*r²=28.26 we can divide by 3.14 to get r² on it's own
r²=28.26/3.14
then we root both sides to get r on it's own
28.26/3.14=9 √9=3
and the diameter is double the radius 3*2=6 so the diameter is 6
Step-by-step explanation:
Answer:
<h2>a. -3</h2>
Step-by-step explanation:
Given Equation :
Which is in slope intercept form :
Where :
m = slope
b = y-intercept.
Thus , in the given Equation , the y-intercept is -3
Answer:
(-3, -6)
explanation:
When reflected across x axis, the x value will be same and y value will become negative.
original coordinates of D: (-3, 6)
- so new coordinates: (-3, (-)6) = (-3, -6)
