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Oduvanchick [21]
3 years ago
10

Answer, show work please

Physics
1 answer:
Brilliant_brown [7]3 years ago
3 0
Π × (16.5^2) × 22.23 = 19013.2878767
just plug in the variables.<span>
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Zain is standing on a bridge. He tosses a ball upwards, which rises, stops, and then falls all the way to the water (30 meters b
IgorC [24]

Answer:

A. 2.41 s.

B. 24.3 m/s.

Explanation:

vf = vi + 2a*t

where, vf = final velocity

= 0 m/s

vi = final velocity

= 1.5 m/s

a = 9.8 m/s^2

A.

ti = 1.5/(9.8 * 2)

= 0.08 s

Vf^2 = Vi^2 + 2a*s

1.5^2 = 2 * 9.8 * s

S = 0.115 m

Time taken to drop into the water,

30.115 = 1.5*to + 4.9*to^2

to = 2.33 s

Total time taken = ti + to

= 2.33 + 0.08

= 2.41 s.

B.

Vo = 0 m/s

S = 30.115 m

Vf = ?

Using,

Vf^2 = Vo^2 + 2*a*s

= sqrt (2*9.8*30.115)

= 24.3 m/s.

7 0
4 years ago
Kevin is a black high school senior. While walking home from a sporting event at school, he sees a police car and decides to tak
RSB [31]

Answer:

Ethnomethodology theory

Explanation:

Take note of the fact that we are told Kevin worries that the police will stop and question him even though he has not done anything wrong.

This statement shows us that Kevin already understood his society from past experiences, and thus he tries to avoid social interactions with particular member of his society (the police) who may be show discrimination towards him.

4 0
3 years ago
Sound travels about four (4) times faster in water than it doss in air. If the speed of sound in air is 343 m/s, how long would
IceJOKER [234]
Any pictures for this question?
4 0
3 years ago
Read 2 more answers
A boy and his skateboard have a combined mass of 65 kg. What is the speed of the boy and skateboard if they have a momentum of 2
Salsk061 [2.6K]
Speed (s) = momentum (M) : mass (m)

s = 275kg * m/sec : 65 kg ≈ 4,23 m/sec
8 0
4 years ago
Read 2 more answers
If the pressure in a gas container that is connected to an open-end U-tube manometer is 116 kPa and the pressure of the atmosphe
tino4ka555 [31]

P = absolute pressure in gas container connected to open-end U-tube = 116 kPa = 116000 Pa

we know that, 1 atm = 101325 Pa   and  1 atm = 760 mm of Hg , hence

P = 116000 Pa  (1 atm/101325 Pa) (760 mm of Hg/1 atm)

P = (116000 x 760/101325)  mm of Hg

P = 870.07 mm of Hg

P₀ = atmospheric pressure = 752 mm Hg

Level of mercury is given as

P' = P - P₀

inserting the values

P' = 870.07 - 752

P' = 118 mm

so correct choice is

d. be 118 mm higher in the arm open to the atmosphere.


5 0
4 years ago
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