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romanna [79]
3 years ago
7

What is the momentum of a 65kg ball rolling at 5 m/s?

Physics
1 answer:
mojhsa [17]3 years ago
7 0

Explanation:

Momentum = mass × velocity

p = (65 kg) (5 m/s)

p = 325 kg m/s

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A satellite in a nearly circular orbit is 2000 km above earth's surface. the radius of earth is approximately 6400 km. if the sa
Ann [662]
Velocity is computed using the formula:

v= \frac{d}{t}
Where:
V = speed
d = distance traveled
t = time/period

First you need to consider that the orbit is circular. To get the measurement or the distance going around Earth, you will need to get the circumference of the path. 

C = 2 \pi r

Where:
C = circumference
π = 3.14
r = radius


The Earth has a radius of 6,400km, but you also need to consider that the satellite is orbiting above the surface of the Earth, so you add in the 2,000km to that radius. 

r = 6,400Km + 2,000Km = 8,400Km

Next step is to insert that into our circumference formula:

C = 2 \pi r
C = 2 \pi 8,400Km
C = 52,778.76 Km

The distance traveled would then be 52,778.76Km

Now that we have the distance, we can then get the velocity:

v= \frac{d}{t}
v= \frac{52,778.76Km}{12hrs}
v= 4,398.23km/hr

The speed of the satellite is 4,398.23km/hr.

7 0
3 years ago
What is the wave speed of a wave that has a frequency of 100Hz and a wavelength of .30m
GrogVix [38]

Here is your answer

We know that

Velocity = Frequency × Wavelength

Here,

Frequency = 100Hz

Wavelength= .30m

So,

Velocity= 100× 0.30 m/s

v= 30 m/s

HOPE IT IS USEFUL

8 0
4 years ago
. A proton, which moves perpendicular to a magnetic field of 1.2 T in a circular path of radius 0.080 m, has what speed? (qp = 1
almond37 [142]

Answer:

9.198\times 10^6 m/s

Explanation:

We are given that

Magnetic field, B=1.2 T

Radius of circular path, r=0.080 m

q_p=1.6\times 10^{-19} C

m_p=1.67\times 10^{-27} kg

\theta=90^{\circ}

We have to find the speed of proton.

We know that

Magnetic force, F=qvBsin\theta

According to question

Magnetic force=Centripetal force

q_pvBsin90^{\circ}=\frac{m_pv^2}{r}

1.6\times 10^{-19}\times 1.2=\frac{1.67\times 10^{-27}v}{0.08}

v=\frac{1.6\times 10^{-19}\times 1.2\times 0.08}{1.67\times 10^{-27}}

v=9.198\times 10^6 m/s

5 0
4 years ago
A measure of the amount of light received on Earth is a star's ____. a. apparent magnitude c. position in space b. absolute magn
Neko [114]
B. I hope this helps!!!
7 0
3 years ago
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Si el atomo anterior de litio eléctricamente neutro ¿cuantos electrones deberia tener?
Lubov Fominskaja [6]
Debe ser de tres electrones
4 0
2 years ago
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