<span>3.36x10^5 Pascals
The ideal gas law is
PV=nRT
where
P = Pressure
V = Volume
n = number of moles of gas particles
R = Ideal gas constant
T = Absolute temperature
Since n and R will remain constant, let's divide both sides of the equation by T, getting
PV=nRT
PV/T=nR
Since the initial value of PV/T will be equal to the final value of PV/T let's set them equal to each other with the equation
P1V1/T1 = P2V2/T2
where
P1, V1, T1 = Initial pressure, volume, temperature
P2, V2, T2 = Final pressure, volume, temperature
Now convert the temperatures to absolute temperature by adding 273.15 to both of them.
T1 = 27 + 273.15 = 300.15
T2 = 157 + 273.15 = 430.15
Substitute the known values into the equation
1.5E5*0.75/300.15 = P2*0.48/430.15
And solve for P2
1.5E5*0.75/300.15 = P2*0.48/430.15
430.15 * 1.5E5*0.75/300.15 = P2*0.48
64522500*0.75/300.15 = P2*0.48
48391875/300.15 = P2*0.48
161225.6372 = P2*0.48
161225.6372/0.48 = P2
335886.7441 = P2
Rounding to 3 significant figures gives 3.36x10^5 Pascals.
(technically, I should round to 2 significant figures for the result of 3.4x10^5 Pascals, but given the precision of the volumes, I suspect that the extra 0 in the initial pressure was accidentally omitted. It should have been 1.50e5 instead of 1.5e5).</span>
Complete Question
The complete question is shown on the first uploaded image
Answer:
The components of reaction at the fixed support are
,
,
,
,
, 
Explanation:
Looking at the diagram uploaded we see that there are two forces acting along the x-axis on the fixed support
These force are 400 N and
[ i.e the reactive force of 400 N ]
Hence the sum of forces along the x axis is mathematically represented as

=> 
Looking at the diagram uploaded we see that there are two forces acting along the y-axis on the fixed support
These force are 500 N and
[ i.e the force acting along the same direction with 500 N ]
Hence the sum of forces along the x axis is mathematically represented as

=> 
Looking at the diagram uploaded we see that there are two forces acting along the z-axis on the fixed support
These force are 600 N and
[ i.e the reactive force of 600 N ]
Hence the sum of forces along the x axis is mathematically represented as

=> 
Generally taking moment about A along the x-axis we have that

=> 
Generally taking moment about A along the y-axis we have that

=> 
Generally taking moment about A along the z-axis we have that

=> 
Answer:
the required minimum magnitude of the force F is 21 N
Explanation:
Given the data in the question,
m = 5 kg
width = 60 cm
height = 80 cm
Let force is F represent in the image below,
so when the block about to rotate normal shifted to edge of cube
mg(w/2) = Fh
F = mg(w/2) / h
we know that g = 9.8 m/s²
we substitute
F = (5 × 9.8 ( 60/2)) / 70
F = (5 × 9.8 × 30 ) / 70
F = 1470 / 70
F = 21 N
Therefore, the required minimum magnitude of the force F is 21 N
There is a total of 6 half lives that need to take place.
ONE HALF LIFE = 200
TWO HALF LIFES = 100
THREE HALF LIFES = 50
FOUR HALF LIFES = 25
FIVE HALF LIFES = 12.5
SIX HALF LIFES = 6.25
The answer is 6.25g