All categories

3 years ago

4. Mr. Ledic works in a coffee shop approximately nine miles from her apartment. She

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

3 0

Answer: 0.3929

Step-by-step explanation:

From the question, we are going to assume that the apartment, park and shop lies on a straight line.

We've been told that Mr. Ledic's apartment to the park is (5x + 6) miles and the trip from the park to the coffee shop is (23x - 8) miles while the coffee shop is nine miles from her apartment. This vsn be written as:

(5x+6)+(23x-8) = 9

28x+6-8=9

28x-2=9

28x=9+2

28x=11

x=11/28

x = 0.3929

Therefore, the value of x is 0.3929

You might be interested in

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

2 years ago

Find the measure of b

amid [387]

Answer: 90°

Step-by-step explanation:

Angle b is vertical to the angle that has a measure of 90°

3 0

3 years ago

What is 107 divided by 97156

belka [17]

107/97156 = 1/908
.......

3 0

3 years ago

Read 2 more answers

What is the pattern to 1,2,4,7,11

Svetllana [295]

Answer:

1+1=2

2+2=4

4+3=7

7+4=11

so the patter is number + natural numbers (serially)

Step-by-step explanation:

4 0

3 years ago

Which of the filling units are units of length

dimaraw [331]

Answer:

The SI unit for length is the meter (abbreviated m); its definition has also changed over time to become more accurate and precise. The meter was first defined in 1791 as 1/10,000,000 of the distance from the equator to the North Pole.

3 0

3 years ago