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3 years ago

Help help help help help bbys help help pls

Mathematics

1 answer:

xeze [42]3 years ago

3 0

1/10 x (34+59t^3 - 50t

Simplify the experience
3.4+5.9t^3 -5t

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<img src="https://tex.z-dn.net/?f=789%20%5Ctimes%20%20%7B8%7D%5E%7B2%7D%20%20%3D%20" id="TexFormula1" title="789 \times {8}^{2}

Nikolay [14]

Answer:

50496

Explanation:

789 × 8 × 8 = 50496

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Hope it helps, if you have any question, comment down below!

5 0

2 years ago

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I could use some help doing this simple math problem lol.

alexira [117]

$D:k-9\geq 0 \wedge k\geq0\\
D:k\geq 9 \wedge k\geq0\\
D:k\geq 9\\
\sqrt{k-9}-\sqrt k=-1\\
\sqrt{k-9}=-1+\sqrt k\\
k-9=(-1+\sqrt k)^2\\
k-9=1-2\sqrt k+k\\
2\sqrt k=10\\
\sqrt k =5\\
k=25

$

7 0

2 years ago

Plz help me I need to know ,What was the towns population in 2005?

Brut [27]

The answer is B: 4,968

5 0

3 years ago

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Helwp please thank uuu!

Minchanka [31]

Step-by-step explanation:

<h3>Given,</h3>

GRAM is a parallelogram
m<GMA = 66°
m<GRP = 32°
m<PAM = 41°

<h3>Solutions:</h3>

i) Since,

Angles on the same side of a transversal in a parallelogram, there sum is 180° so,

<RGM + <GMA = 180°

=> <RGM = 180° - <GMA

=> <RGM = 180° - 66°

=> <RGM = 114° (Ans)

ii) Since,

Opposite angles of a diagonal as a transversal (here RM) are equal so,

<GRP = <PMA = 32°

As we have <GMA = 66° so,

=> <GMP = <GMA - <PMA

= 66° - 32°

=> <GMP = 34° (Ans)

iii) Since,

Opposite angles of a parallelogram are equal so,

<RGM = <RAM = 114°

As we have <PAM = 41° so,

=> <GAR = <RAM - <PAM

= 114° - 41°

=> <GAR = 73° (Ans)

iv) Since,

We got <PMA = 32° and <PAM = 41°, so by angle sum property of a triangle PMA,

=> <MPA = 180° - 32° - 41°

=> <MPA = 107° (Ans)

7 0

2 years ago

If the team needs 3 beams and 6 channels will the grant cover the cost (grant is 75.00)

Nadusha1986 [10]

Answer:

Ilan lahat Ang kabuuang bilang ng mga nakalarawang bagay

8 0

2 years ago

Read 2 more answers