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2 years ago

5

Can someone help me do this question :(

2 answers:

Katen [24]2 years ago

4 0

Answer:

20 is the answer

Step-by-step explanation:

netineya [11]2 years ago

3 0

Step-by-step explanation:

Have a look at the attachment first to avoid any confusion.

Total number of cubes therefore, is 17.

1 from top

4 + 4 = 8 at second back row

4 again in lower front row

2 + 2 = 4 in the front.

So, 17 is the unit cubes in the figure.

Hope it helps :)

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Find the value of root 121 + 3 over root 125

NemiM [27]

Answer:

$\mathrm{Decimal:\quad }\:1.25219\\\frac{14\sqrt{5}}{25}$

Step-by-step explanation:

$\frac{\sqrt{121}+3}{\sqrt{125}}\\\sqrt{125}=5\sqrt{5}\\=\frac{\sqrt{121}+3}{5\sqrt{5}}\\\sqrt{121}=11\\=\frac{11+3}{5\sqrt{5}}\\\mathrm{Add\:the\:numbers:}\:11+3=14\\=\frac{14}{5\sqrt{5}}\\\mathrm{Rationalize\:}\frac{14}{5\sqrt{5}}:\quad \frac{14\sqrt{5}}{25}\\=\frac{14\sqrt{5}}{25}$

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3 years ago

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Please help me. I desperately need to pass Math T-T

Ad libitum [116K]

Answer:

60 degrees

Step-by-step explanation:

C = 2(pi)r

The radius is 12 cm. We can find the circumference of a circle with radius 12 cm.

C = 2(pi)r = 2(3.14)(12 cm) = 75.36 cm

The length of the arc of the sector is 12.56 cm.

We can find the fraction this length is of the full circumference.

(12.56 cm)/(75.36 cm) = 1/6

The length of the arc of this sector is 1/6 the length of the circumference of the entire circle.

That means the angle of the sector is 1/6 the angle of an entire circle.

An entire circle has a central angle of 360 degrees.

1/6 * 360 degrees = 60 degrees

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2 years ago

3/4 times the amount of 20

klio [65]

Answer:

$= { \rm{ \frac{3}{4} \times 20}} \\ \\ = { \rm{ \frac{60}{4} }} \\ \\ = { \boxed{ \tt{ \: \: 15 \: \: }}}$

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2 years ago

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PLEASE PLEASE ANSWER!

muminat

The area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

Solution:

Given radius = 4 cm

Diameter = 2 × 4 = 8 cm

Let us first find the area of the semi-circle.

Area of the semi-circle = $\frac{1}{2}\times \pi r^2$

$$=\frac{1}{2}\times \pi\times 4^2$

$$=\frac{1}{2}\times \pi\times 16$

Area of the semi-circle = $$8\pi$ cm²

Angle in a semi-circle is always 90º.

∠C = 90°

So, ABC is a right angled triangle.

Using Pythagoras theorem, we can find base of the triangle.

$AC^2+BC^2=AB^2$

$AC^2+4^2=8^2$

$AC^2=64-16$

$AC^2=48$

$AC=4\sqrt{3}$ cm

Base of the triangle ABC = $4\sqrt{3}$ cm

Height of the triangle = 4 cm

Area of the triangle ABC = $\frac{1}{2}\times b \times h$

$$=\frac{1}{2}\times 4\sqrt{3} \times 4$

Area of the triangle ABC = $8\sqrt{3}$ cm²

Area of the shaded region

= Area of the semi-circle – Area of the triangle ABC

= $$8\pi \ \text{cm}^2-8\sqrt{3}\ \text{cm}^2$

= $$8(\pi \ -\sqrt{3})\ \text{cm}^2$

Hence the area of the shaded region is $$8(\pi \ -\sqrt{3})\ \text{cm}^2$ .

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2 years ago

What is 4xy + x + 2xy

Vika [28.1K]

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2 years ago

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