Answer:
1.
y = 20(11) + 300 = 520
y = 5(11)(11) = 605
y = 10(1.4)^11 = 404.96
hence the quadratic formula - y = 5x^2 has the largest y-value
2.
y = 20 (14) + 300 = 580
y = 5 (14) (14) = 980
y = 10(1.4)^ 14 = 1111.20 > this is greater than both equations above
14 is the smallest value of x for which the value of the exponential equation is greater than the values of both the linear and quadratic functions
Step-by-step explanation:
1. Quadratic
2. x = 14
1. At x = 11
linear: y=20(11) + 300 = 520
Quadratic: y=5× 11² = 605
Exponential: y=10(1.4)¹¹ = 404.956517
2. 10(1.4^x) > 20x + 300
1.4^x > 2x + 30
1.4^x - 2x - 30 > 0
Using trial method:
x > 11
10(1.4^x) > 5x²
1.4^x - 0.5x² > 0
Using trail method:
x > 13
The smallest positive integer which satisfies both inequalities is 14
y=3/4 x+1
first you start with y=mx+b find the y intercept first which is 1 next you just count down the block which is 3 then count to the right till you find a spot where it lands which would get you y=3/4+1
74 hope this works if not I'm sorry
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