Answer:
(x+5)² = 16
Solution: -1 and -9
Step-by-step explanation:
Given the quadratic equation X^2+10x+22=13
Subtract 22 from both sides
X^2+10x+22-22=13-22
x^2+10x = -9
Complete the square
Add the square of half of coefficient of x to both sides
coefficient of x = 10
half of coefficient of x = 10/2 = 5
square of half of coefficient of x= 5² = 25
Add 25 to both sides
x²+10x + 25 = -9+25
(x+5)² = 16
Hence the required equation is (x+5)² = 16
(x+5)² = 16
square root both sides
√(x+5)² = √16
x+5 = √16
x +5 = ±4
x = +4 - 5 and -4-5
x = -1 and -9
Hence the solution to the equation is -1 and -9
Answer: 11.125
Step-by-step explanation:
Answer:
see explanation
Step-by-step explanation:
the equation of a parabola in vertex form is
y = a(x - h)² + k
where (h, k) are the coordinates of the vertex and a is a multiplier
Given the equation in standard form : ax² + bx + c : a ≠ 0
then the x-coordinate of the vertex is
= - 
j(x) = x² - 12x + 7 is in standard form
with a = 1, b = - 12 and c = 7, hence
= - 
= 6
substitute x = 6 into j(x) for y- coordinate
y = 6² - 12(6) + 7 = 36 - 72 + 7 = - 29
vertex = (6, - 29 ) and
j(x) = (x - 6)² - 29 ← equation in vertex form
The equation is like.
= 3(x)-17
when u see less than or more than u flip it its a rules :D
hope this helps..
