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hram777 [196]
3 years ago
10

Help out?? Mathematics image.

Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0

Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40°  (17) ABC <em>or</em>  180° - CD (18) BC - 140°  (19) ABC = 150°

<u>Step-by-step explanation:</u>

12) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(80 - 40) = ∠1

\frac{1}{2}(40) = ∠1

20 = ∠1

13) \frac{1}{2}(UV + ST) = ∠2

\frac{1}{2}(70 + 30) = ∠2

\frac{1}{2}(100) = ∠2

50 = ∠2

14) \frac{1}{2}(VB - BS) = ∠3

\frac{1}{2}(60 - 30) = ∠3

\frac{1}{2}(30) = ∠3

15 = ∠3

15) \frac{1}{2}(UV - ST) = ∠1

\frac{1}{2}(UV - 20) = 30

UV - 20 = 60

UV = 80

16) ∠1 = arc AB

     ∠1 = 40

              arc AB = 40

17) arc AB + arc BC = arc AC

                               = 180 = arc CD  

18) ∠1 + ∠2 + ∠3 = 180

   20 + ∠2  + 20 = 180

            ∠2 + 40 = 180

                      ∠2  = 140

19) ∠1 + ∠ 2 = arc ABC

     ∠1 + ∠2 + ∠3 = 180

    arc ABC + 30 = 180

            arc ABC = 150


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When 1600 is increased by 20% and the resulting number is decreased by y% the answer is 1536. Find the value of y?
svet-max [94.6K]
100% = 1600
120% = 1920

1920/120 = 1536/y
1920y = <span>184320 (cross multiply)
y = 96%
decrease of 24% from 1920</span>
7 0
3 years ago
Which conic's equation has 2 squares with the same signs and different leading coefficients?
Romashka [77]

We want to see which is the conic equation that has 2 squares with the same sign and different leading coefficients.

We will see that it is the equation of the ellipse.

Now let's see why that is the correct answer.

The general conic equation is of the form:

A*(x - a)^2 + B*(x - b)^2 = R^2

Where A and B are the leading coefficients, (a, b) is the center of the figure, and R is the average radius of the figure.

For example, if A = B, this would be the equation of a circle, but we must have two different leading coefficients.

If we write:

A = 1/C

B = 1/K

(both are positive, because "it has two squares with the same signs").

Then we get the equation:

\frac{ (x - a)^2}{C} + \frac{(x - b)^2}{K} = R^2

We get the equation we wanted.

The same sign in both square parts and different leading coefficients.

The above equation is the general equation of an ellipse.

If you want to learn more, you can read:

brainly.com/question/10311514

7 0
2 years ago
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Alborosie

Answer:

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Step-by-step explanation:

5 0
3 years ago
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den301095 [7]

Answer:

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6 0
3 years ago
Read 2 more answers
Which of the following illustrates a phase shift?
Natasha_Volkova [10]

<u>Answer:</u>

A. y = -2 - cos(x-π)


<u>Explanation:</u>

<u>The general form of the trig equation is:</u>

y = A sin (Bx + C) + D

where:

A is the amplitude

\frac{2\pi}{B} is the period

\frac{-C}{B} is the phase shift

D is the vertical shift


<u>Now, let's check the choices:</u>

<u>A. y = -2 - cos(x-π)</u>

\frac{-C}{B} = \frac{\pi}{1}  = \pi

Therefore, the function has a phase shift of π


<u>B. y = 3 cos(4x)</u>

\frac{-C}{B} = \frac{0}{4} = 0

Therefore, the function has no phase shift


<u>C. y = tan(2x)</u>

\frac{-C}{B} = \frac{0}{2} = 0

Therefore, the function has no phase shift


<u>D. y = 1 + sin(x)</u>

\frac{-C}{B} = \frac{0}{1} = 0

Therefore, the function has no phase shift


<u>Based on the above,</u> the correct answer is A


Hope this helps :)

3 0
3 years ago
Read 2 more answers
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