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Bogdan [553]
3 years ago
7

A circular hedge surrounds a sculpture on a square base. The radius of the hedge is 6x. The side length of the square sculpture

base is 4x. What is that area of the hedge? Write your answer in factored form.
Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0
Hi, thank you for posting your question here at Brainly.

Since the hedge is surrounding the square base, the area of the base can be determined by subtracting the area of the base from the hedge.

A = pi*r^2 - (4x)^2
A = pi*(6x)^2 - (4x)^2
A = 2x^2*(3pi - 2)

I hope I was able to answer your question. Have a good day.
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20 points!
meriva

All circles are similar because all circle have same shape.

However Two circles are congruent , if and only if their radii are congruent.

In our question we are asked when are all circles similar given if their radii are congruent.

So we can say this statement is false because no matter the radii are congruent or not  , two or more circles are always similar because of their same shape no matter what the measure of their radii is. Only if we are asked when they are congruent, we will consider the radii part.

Answer is false.

4 0
3 years ago
Read 2 more answers
Find the domain of the function.<br><br><br><br> f(x) = -5x + 3
Sedaia [141]

Enter a problem...

Calculus Examples

Popular Problems Calculus Find the Domain and Range f(x)=5x-3

f

(

x

)

=

5

x

−

3

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

x

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x

∈

R

}

The range is the set of all valid

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Interval Notation:

(

−

∞

,

∞

)

Set-Builder Notation:

{

y

|

y

∈

R

}

Determine the domain and range.

Domain:

(

−

∞

,

∞

)

,

{

x

|

x

∈

R

}

Range:

(

−

∞

,

∞

)

,

{

y

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y

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3 0
2 years ago
Jacob transformed quadrilateral FGHJ to F'G'H'J'.
Rudik [331]

Answer:

A. Reflection across the line x = 1

Step-by-step explanation:  

Please find the attachment.

We have been given that Jacob transformed quadrilateral FGHJ to F'G'H'J'.  We are asked to find which transformation Jacob used to reflect FGHJ to F'G'H'J'.

Since we know that while reflecting a figure, the line of reflection will lie between the original figure and reflected figure. Each point of the reflected figure will have the same distance from the line of reflection as the corresponding point of the original figure.              

Now let us see our given choices one by one.

A. Reflection across the line x = 1.

Upon looking at point G and G' we can see that both points are equidistant (2 units) from the line x=1. Other corresponding points of both quadrilaterals are also equidistant from line x=1, therefore, Jacob used the reflection across the line x=1 to transform quadrilateral FGHJ to F'G'H'J'.

B. Reflection across the line y = 1 .      

If Jacob had reflected quadrilateral across line y=1, the points of quadrilateral F'G'H'J' will lie in second and third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option B is not a correct choice.

C. Reflection across the line y-axis.

If Jacob had reflected quadrilateral across y-axis, the coordinates of points of quadrilateral F'G'H'J' will be G'(1,4), H'(1,2), J'(4,0) and F'(2,5). Therefore, option B is not a correct choice.

D.  Reflection across the x -axis.

If Jacob had reflected quadrilateral across x-axis, the points of quadrilateral F'G'H'J' will lie in third quadrant. We can see from our graph that F'G'H'J' lies in 1st quadrant, therefore, option D is not a correct choice.

3 0
3 years ago
What is the constant of proportionality in the table shown ?
solmaris [256]

Answer:

9

Step-by-step explanation:

6 0
3 years ago
Find the value of the following expression:
Phoenix [80]

(3^8 ⋅ 2^-5 ⋅ 9^0)^-2 ⋅ (2^ -2 / 3^3) ^4 ⋅ 3^28 =

(6561 * 0.03125 * 1)^2 * (0.00925)^4 * 22876792454961 =

42037.81348 * 0.00000000732094 * 22876792454961 =

7040477235.56798349

 round answer as needed

8 0
3 years ago
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