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ira [324]
3 years ago
12

20 POINTS to anyone who can help me with this!

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0
Image:
S= -10,7
R: -14,4
T: -5,4

Pre-image
R: -10,-2
S: -6,1
T: -1,-2

The vertices of the image move 4 units to the rigth and 6 units down.
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Determine if the number provided is a solution to the equation: 4x-1=2; when x = 1/2
Tomtit [17]

Hey!

------------------------------------------------

Steps To Solve:

~Substitute

4(1/2) - 1 = 2

~Simplify

2 - 1 = 2

1 ≠ 2

------------------------------------------------

Answer:

\large\boxed{\frac{1}{2}~is~not~a~solution~to~the~equation }

------------------------------------------------

Hope This Helped! Good Luck!

4 0
3 years ago
Daisy, Kyra, and Ana will share the cost to buy their teacher a present for
Vlad [161]
Kyra is paying $21 (60*.35)
Daisy is paying $24 (60*.40)
Ana is paying $15 (60-21-24)
8 0
4 years ago
Simplify without the absolute value<br> |x+3| ; if x=2
Alja [10]

ANSWER

5

EXPLANATION

We want to simplify:

|x + 3|

when x=2.

We substitute x=2 into the absolute value expression to obtain:

|2 + 3|  =  |5|

The about value of 5 means what is the distance of 5 from zero on the real number line.

|2 + 3|  =  |5|  = 5

4 0
4 years ago
Read 2 more answers
Please helpp and if you could, could you explain in detail how you got the answer? (You don’t have to if you don’t want to)
Law Incorporation [45]

Answer:

A

Step-by-step explanation:

The y-intercept is the 'b' in y=mx+b. In the graph, the y-intercept is -5. In the equation, the y-intercept is 5.

-5 < 5.

-hope it helps

3 0
2 years ago
Pythagorean triples are given by the formulas x2 - y2, 2xy, and x2 + y2. Use the formulas for the Pythagorean triples to prove w
Arte-miy333 [17]
Let k be an integer. Suppose there is a triangle with legs of length 16 and 2k+1. Then by the Pythagorean theorem, the length of the hypotenuse should be

\sqrt{16^2+(2k+1)^2}=\sqrt{4k^2+4k+257}

The formulas for Pythagorean triples say that if the legs are integers, then so must be the hypotenuse, because if x=16 and y=2k+1 are integers, then so are x^2-y^2, 2xy, and x^2+y^2.

However, 4k^2+4k+257 is not a perfect square trinomial, which means for any integer k, the length of the hypotenuse is not an integer, so such a triangle doesn't exist.
4 0
3 years ago
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