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a_sh-v [17]
3 years ago
14

The Harper family is traveling to visit friends. The distance to the friend’s house is 276.45 miles. It takes the family 5.82 ho

urs to complete the trip.
Rate is found by dividing distance by time.

What is the rate for the family’s trip in miles per hour?

need now plz
Mathematics
2 answers:
otez555 [7]3 years ago
7 0

Answer: 47.5 miles per hour

Step-by-step explanation:

We know that ,

\text{Speed}=\dfrac{\text{Distance}}{\text{Time}}

Given : The distance to the friend’s house is 276.45 miles. It takes the family 5.82 hours to complete the trip.

i.e. Distance = 276.45 miles

Time = 5.82 hours

Then, the rate(speed) for the family’s trip in miles per hour will be :-

\text{Speed}=\dfrac{276.45}{5.82}=47.5\text{ miles per hour}

Hence, the rate for the family’s trip = 47.5 miles per hour

IceJOKER [234]3 years ago
5 0
The rate is 47.5 miles per hour 
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Answer:

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b) Rachel, because her time had the lowest z-score.

Step-by-step explanation:

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In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

The lower the time, the better the runner is. So whoever's time has a lower z-score is a better runner. So initially, we find the z-score of each student's time.

An elementary school class ran 1 mile in an average of 11 minutes with a standard deviation of 3 minutes. Rachel, a student in the class, ran 1 mile in 8 minutes.

This means that for Rachel's time, we have that X = 8, \mu = 11, \sigma = 3. So

Z = \frac{X - \mu}{\sigma}

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A junior high school class ran 1 mile in an average of 9 minutes, with a standard deviation of 2 minutes. Kenji, a student in the class, ran 1 mile in 8.5 minutes.

This means that for Kenji's time, we have that X = 8.5, \mu = 9, \sigma = 2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.5 - 9}{2}

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A high school class ran 1 mile in an average of 7 minutes with a standard deviation of 4 minutes. Nedda, a student in the class, ran 1 mile in 8 minutes.

This means that for Nedda's time, we have that X = 8, \mu = 7, \sigma = 4. So

Z = \frac{X - \mu}{\sigma}

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(a) Why is Kenji considered a better runner than Nedda, even though Nedda ran faster than he?

Kenji's time had a lower z-score, which means that he is better compared to other runners on his level, and better to his peers compared to Nedda.

(b) Who is the fastest runner with respect to his or her class? Explain why

Rachel, because her time had the lowest z-score.

8 0
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