All categories

2 years ago

Y = -(x + 5)(x + 1)

Mathematics

1 answer:

frez [133]2 years ago

8 0

Answer:

dffdfdfdfdfsdewered

Step-by-step explanation:

You might be interested in

Please help ASAP I’m having trouble with these problems there’s only 3 :(

masya89 [10]

Answer:

sorry i cant read it

Step-by-step explanation:

6 0

2 years ago

What is the present value of $3,000 per year for 9 years discounted back to the present at 10 percent?

Studentka2010 [4]

Answer:

$17,277.07

Step-by-step explanation:

Present value of annuity is the present worth of cash flow that is to be received in the future, if future value is known, rate of interest is r and time is n then PV of annuity is

PV of annuity = $\frac{P[1-(1+r)^{-n}]}{r}$

= $\frac{3000[1-(1+0.10)^{-9}]}{0.10}$

= $\frac{3000[1-(1.10)^{-9}]}{0.10}$

= $\frac{3000[1-0.4240976184]}{0.10}$

= $\frac{3000(0.5759023816)}{0.10}$

= $\frac{1,727.7071448}{0.10}$

= 17,277.071448 ≈ $17,277.07

3 0

2 years ago

One household is to be selected at random from a town. The probability that the household has a cat is 0.20.2 . The proba

dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

$A = a + (A \cap B)$

In which a is the probability that a household has a cat but not a dog and $A \cap B$ is the probability that a household has both a cat and a dog.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that the household has a cat or a dog is 0.5

$a + b + (A \cap B) = 0.5$

The probability that the household has a dog is 0.4

$B = 0.4$

$B = b + (A \cap B)$

$b = 0.4 - (A \cap B)$

The probability that the household has a cat is 0.2.

$A = 0.2$

$A = a + (A \cap B)$

$a = 0.2 - (A \cap B)$

$a + b + (A \cap B) = 0.5$

$0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5$

$A \cap B = 0.1$

What is the probability that the household has a dog, given that the household has a cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

$P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5$

There is a 50% probability that the household has a dog, given that the household has a cat.

4 0

2 years ago

You are painting the outside of 28 foot fence that goes around a square graden there are 4equal sections you have painted 1/2 of

Cloud [144]

Answer:

1/8

Step-by-step explanation:

If there are 4 sections then each section is 1/4. You need to find 1/2 of one section so you will need to multiply 1/2 times 1/4 which equals 0.125 or 1/8.

4 0

2 years ago

Quarter of 8 I don't have a clue how to do it

Anit [1.1K]

A quarter is 4 pieces.
So its 8÷4=2
Hence, a quarter of 8 is 2.

3 0

3 years ago

Y = -(x + 5)(x + 1)​

Y = -(x + 5)(x + 1)