How can energy transform from one form to another

a student used 10 mL water instead of 30 mL for extraction of salt from mixture. How may this change the percentage of NaCl extr

Anit [1.1K]

It will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

If it is known that solubility of NaCl is 360 g/L, let's find out how many NaCl is in 30 mL of water:

360 g : 1 L = x g : 30 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = x g : 30 mL

Now, crossing the products:
x · 1,000 mL = 360 g · 30 mL
x · 1,000 mL = 10,800 g mL
x = 10,800 g ÷ 1,000
x = 10.8 g

So, from 30 mL mixture, 10.8 g of NaCl could be extracted.

Let's calculate the same for 10 mL water instead of 30 mL.

360 g : 1 L = x g : 10 mL

Since 1 L = 1,000 mL, then:
360 g : 1,000 mL = x g : 10 mL

Now, crossing the products:
x · 1,000 mL = 360 g · 10 mL
x · 1,000 mL = 3,600 g mL
x = 3,600 g ÷ 1,000
x = 3.6 g

So, from 10 mL mixture, 3.6 g of NaCl could be extracted.

Now, let's compare:
If from 30 mL mixture, 10.8 g of NaCl could be extracted and from 10 mL mixture, 3.6 g of NaCl could be extracted, the ratio is:
3.6/10.8 = 1/3

Therefore, it will be extracted only 1/3 of NaCl less in 10 mL of water than in 30 mL of water.

5 0

3 years ago

Can electricity cause a chemical change?

KiRa [710]

Yes it can cause chemical change

6 0

3 years ago

What is the degree of unsaturation for a compound with the molecular formula c6h6?

Nesterboy [21]

Answer:

The degree of unsaturation for a compound with molecular formula C₆H₆ is 4.

Explanation:

The degree of unsaturation is calculated through the following formula:

2n + 2 - H / 2

n = Total number of hydrogen in given compound

There are six hydrogen in given compound, now we will calculate the degree of unsaturation by putting the value of n= 6

(2(6) + 2 - 6 )/ 2

(12+ 2 - 6) / 2

(14 - 6) /2

8 / 2 = 4

The degree of unsaturation for a compound with molecular formula C₆H₆ is 4.

The given compound is benzene and degree of unsaturation is 4. Three double bond and one ring.

6 0

4 years ago

Calculate the concentration of OH in a solution that contains 3.9 10-4 M H30 at 25°C. Identify the solution as acidic, basic or

Norma-Jean [14]

Answer:

Option A) 2.6 × 10⁻¹¹ M, acidic.

Explanation:

The ion-product constant of water $K_{\rm w}$ gives a relationship between $\rm [H_3O^{+}]$ and $\rm [OH^{-}]$ :

$K_{\rm w} = \rm [H_3O^{+}]\cdot [OH^{-}]$ .

The exact value of $K_{\rm w}$ depends on the temperature. Under $\rm 25^{\circ}C$ , $K_{\rm w} \approx 1^{-14}$ .

The question states that $\rm [H_3O^{+}] = 3.9\times 10^{-4}\; M$ . As a result,

$\begin{aligned} {\rm [OH^{-}]} &= \frac{K_{\rm w}}{[{\rm H_3O^{+}}]}\\ &\approx\frac{1^{-14}}{3.9\times 10^{-4}} && \rm {\leftarrow Only~under~25^{\circ}C.}\atop{}\\&\approx \rm 2.6\times 10^{-11}\; M\end{aligned}$ .

A solution is acidic if $\rm [H_3O^{+}] > [OH^{-}]$ .
A solution is neutral if $\rm [H_3O^{+}] = [OH^{-}]$ .
A solution is acidic if $\rm [H_3O^{+}] < [OH^{-}]$ .

$\rm [H_3O^{+}] > [OH^{-}]$ for this solution. As a result, this solution is acidic.

8 0

3 years ago

7,5,3,6,9 what three numbers add up to 12

mars1129 [50]

Explanation:

3+3+6=12 is the three numbers adding up to 12

7 0

3 years ago