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Marat540 [252]
3 years ago
6

Assume you completed the reaction below in the lab. You began with 22 grams of nitrogen, and produced 19 grams of ammonia (NH3).

According to the mass calculations, you should be able to produce 26 grams of ammonia. What is the percent yield? N2 + 3 H2 → 2 NH3
Chemistry
1 answer:
Roman55 [17]3 years ago
8 0

Answer:

The percent yield is 73,07%

Explanation:

N2 + 3 H2 → 2 NH3

If you be able to produce 26 grams of ammonia, that is the 100 % yield reaction so:

26 grams ___ 100 %

19 grams ____ (19. 100) / 26 = 73,07%

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Many chemistry problems result in equations of the form
Gnom [1K]

Answer:

When this equation is solved, the two values of the unknown are 0.0643 and -0.082

Explanation:

Given

1.77 * 10^{-2} = \frac{x^2}{0.298 - x} --- the actual equation

Required

The values of x

We have:

1.77 * 10^{-2} = \frac{x^2}{0.298 - x}

Cross Multiply

1.77 * 10^{-2} * (0.298 - x)= x^2

Multiply both sides by 100

1.77  * (0.298 - x)= 100x^2

Open bracket

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Rewrite as:

100x^2 + 1.77x - 0.52746 =0

Using quadratic formula:

x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}

Where:

a = 100; b = 1.77; c = -0.52746

So, we have:

x = \frac{-1.77 \± \sqrt{1.77^2 - 4*100*- 0.52746 }}{2*100}

x = \frac{-1.77 \± \sqrt{214.1169}}{2*100}

x = \frac{-1.77 \± 14.63}{200}

Split

x = \frac{-1.77 + 14.63}{200}\ or\ x = \frac{-1.77 - 14.63}{200}

x = \frac{12.86}{200}\ or\ x = \frac{-16.40}{200}

x = 0.0643\ or\ x = -0.082

3 0
3 years ago
Can someone please help me? i can give brainliest!!! :(
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Answer:

it would be 5 and 3??? right

Explanation:

hope this helps

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