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Masja [62]
3 years ago
15

A sea turtle made 460 dives in 12 hours At this rate how many dives did it do in 3 hours show your work

Chemistry
1 answer:
Montano1993 [528]3 years ago
3 0
12/3=4
460/4=115
The sea turtle made 115 dives in 3 hours.
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What is true about all chemical equations?<br> Links are reported
Vanyuwa [196]

Answer:Your answer is A

Explanation:

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6 0
3 years ago
Metallic properties tend to increase in which direction on the periodic table
tresset_1 [31]
Metallic properties head to the left.
3 0
2 years ago
A liquid-phase isomerization is carried out in a 1000-gal CSTR that has a single impeller located halfway down the reactor. The
igomit [66]

Answer:

The conversion achieved for the first CSTR impeller is 0.382

Discrepancy = 0.188

Explanation:

The impeller divides the CSTR into 2 equal reactors of volume 500gal

Using V = FaoX/ (-ra)

500gal = Fao×Xa/[(KCao^2( 1 -X1)^2]

500gal = CaoVoX1/ KCao^2(1-X1)

500gal= 500gal × X1'/(1 - X1)^2

(1 -X1)^2 = X1

X1^2 - 3X1 + 1 = 0

X1= 0.382

Conversion achieved in the first CSTR is 0.382

Actual measured CSTR = 57% =57/100=0.57

Discrepancy in the conversions= 0.57 -0.383 =0.188

8 0
2 years ago
Platinum crystallizes with the face-centered cubic unit cell. The radius of a platinum atom is 139 pm. Calculate the edge length
horrorfan [7]

Answer:

Length = 393pm, Density = 21.3 g/cm^3.

Explanation:

From the question above, we have the following parameters or data which is going to aid in solving the above Question.

=> The radius of a platinum atom = 139 pm.

Therefore, the length can be calculated by making use of the formula given below:

Length = 2 √( 2r) = 2 × √ (2 × 139 × 10^-12m ) = 393 × 10^-10 m = 393pm.

The density can be calculated by making use of the chemical formula given below:

Density = mass ÷ volume = (195.064/ 6.02 × 10^23) ÷ (3.93 × 10^-10/ 10^-2) = 21.3 g/cm^3.

3 0
3 years ago
A solution is made by dissolving 0.565 g of potassium nitrate in enough water to make up 250. mL of solution. What is the molari
aalyn [17]
<h3>Molar mass of Potassium Nitrate:-</h3>

\\ \large\sf\longmapsto KNO_3

\\ \large\sf\longmapsto 39u+14u+3(16u)

\\ \large\sf\longmapsto 53u+48u

\\ \large\sf\longmapsto 101u

\\ \large\sf\longmapsto 101g/mol

Now

\boxed{\sf No\:of\:moles=\dfrac{Given\:mass}{Molar\:mass}}

\\ \large\sf\longmapsto No\:of\:moles=\dfrac{0.565}{101}

\\ \large\sf\longmapsto No\:of\:moles=0.005mol

We know

\boxed{\sf Molarity=\dfrac{Moles\:of\:solute}{Vol\:of\:Solution\:in\:L}}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{\dfrac{250}{1000}L}

\\ \large\sf\longmapsto Molarity=\dfrac{0.005}{0.250}

\\ \large\sf\longmapsto Molarity=0.02M

8 0
3 years ago
Read 2 more answers
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