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mihalych1998 [28]
3 years ago
15

The following temperatures were recorded in Pasadena for a week in April: 87, 85, 80, 78, 83, 86, 90. Determine the interquartil

e range. Type a numerical answer in the space provided. Do not include spaces in your answer.
Mathematics
1 answer:
faltersainse [42]3 years ago
8 0
Find the median first. 

78, 80, 83, 85, 86, 87, 90. The middle one is 85, so there's the median. Take the upper half of this set, not including the median, 85, and then subtract 86 from 90. This is 4, so this is the interquartile range. 
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PLEASE HELP ASAP
Evgen [1.6K]

Answer: I'm not sure how to interpret "If 4 (A) between 5/8 and 4/5." If the sentence was supposed to read:

"Is 4:

(A) between 5/8 and 4/5

(B) between 1 and 2

(C) between 0 and 2

(D) between 1/2 and 1

(E) cannot be determined

Step-by-step explanation: If this is the correctly rewritten question, then the answer is NO to all the options. If I have misinterpreted the question, please clarify.

6 0
3 years ago
suppose that during one period of extreme cold the average daily temp decreased 1 1/2 Fahrenheit each day how many days did it t
Nina [5.8K]

Answer:

The temperature decreased by 9 °F in <u>6 days.</u>

Step-by-step explanation:

Let the number of days it takes for the temperature to decrease by 9 °F be x.

Given:

Average daily temperature decreases by 1\frac{1}{2} °F.

Decrease of temperature in 1 day = 1\frac{1}{2}= 1.5 °F.

∴ Decrease in temperature in x days is 1.5x.

Now, as per question, decrease in temperature in 'x' days is 9 °F.

Therefore, 1.5x=9

x=\frac{9}{1.5}

x=6

Therefore, the temperature decreased by 9 °F in 6 days.

7 0
3 years ago
Solve the equation: k^2+5k+13=0
mr_godi [17]

Step-by-step explanation:

k² + 5k + 13 = 0

Using the quadratic formula which is

x =  \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}  \\

From the question

a = 1 , b = 5 , c = 13

So we have

k =  \frac{ - 5 \pm \sqrt{ {5}^{2} - 4(1)(13) } }{2(1)}  \\  =  \frac{ - 5 \pm \sqrt{25 - 52} }{2}  \\  =  \frac{ - 5 \pm \sqrt{ - 27} }{2}  \:  \:  \:  \:  \:  \:  \\  =  \frac{ - 5  \pm3 \sqrt{3}  \: i}{2}  \:  \:  \:  \:  \:  \:

<u>Separate the solutions</u>

k_1 =  \frac{ - 5 + 3 \sqrt{3} \: i }{2}  \:  \:  \:  \: or \\ k_2 =  \frac{ - 5 - 3 \sqrt{3}  \: i}{2}

The equation has complex roots

<u>Separate the real and imaginary parts</u>

We have the final answer as

k_1 =  -  \frac{5}{2}  +  \frac{3 \sqrt{3} }{2}  \: i \:  \:  \:  \: or \\ k_2 =  -  \frac{5}{2}  -  \frac{3 \sqrt{3} }{2}  \: i

Hope this helps you

8 0
3 years ago
How would eight billion, nine hundred seventy-seven thousand, thirteen be written in standard form?
zheka24 [161]

Answer:

8 billion > 8,000,000,000

977 thousand > 977,000

13> 13

8,000,977,013

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A problem states: "There are 2 more horses than cows in a field. There are 15 animals in the field in all. How many horses are t
mash [69]
Let h =  the number of horses in the field
Let c =  number of cows in the field

There are 2 more horses than cows in the field. Therefore
h = c + 2
 or
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There are 15  animals in the field. Therefore
h + c = 15              (2)

Substitute (1) into (2).
h + (h - 2) = 15
2h - 2 = 15

Answer:
The correct equation is 
2h - 2 = 15
4 0
3 years ago
Read 2 more answers
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