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3 years ago

What’s the correct answer for this ?

Mathematics

1 answer:

icang [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Since both the triangles as kept separately are similar, so we'll take proptionality of their sides to find one side

MP/ML=MN/MK

20/28=35/MK

CROSS MULTIPLYING

20×MK=28×35

MK=980/20

MK=49

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What should be done to both sides of the equation in order to solve y + 8.5 = 17.2?

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Answer:

Subtract 8.5

Step-by-step explanation:

To solve the equation, y has to be isolated (only y will be on one side of the equation)

To do this, we have to get rid of the 8.5, so it has to be subtracted from both sides.

So, the correct answer is subtract 8.5

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What is the value of x? 27(x+4)=−6 −35 −25 25 35

Oksanka [162]

x = -38/9 !!!

27(x+4)=−6

Step 1: Simplify both sides of the equation.

27(x+4)=−6

(27)(x)+(27)(4)=−6 (Distribute)

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Step 2: Subtract 108 from both sides.

27x+108−108=−6−108

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3 years ago

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3 years ago

A company manufactures and sells x television sets per month. The monthly cost and price-demand equations are C(x)=72,000+60x

myrzilka [38]

Answer:

Step-by-step explanation:

Given

Cost Price $c(x)=72000+60x$

Price $p(x)=300-\frac{x}{20}$

Revenue generated $R(x)=P(x)\times x$

where x=no of units

$R(x)=300x-\frac{x^2}{20}$

To get maxima and minima differentiate R(x)

$\frac{\mathrm{d} R(x)}{\mathrm{d} x}=0$

$\frac{\mathrm{d} R(x)}{\mathrm{d} x}=300-2\times \frac{x}{20}=0$

$300=2\times \frac{x}{20}$

$x=3000$

maximum Revenue $R(x)=(300-\frac{300}{20})\times 300=4,50,000$

(b)Profit=Revenue - cost

$Profit=xp(x)-c(x)$

$Profit=300x-\frac{x^2}{20}-72000-60x$

$Profit(z)=240x-\frac{x^2}{20}-72000$

differentiate Profit to get maximum value

$\frac{\mathrm{d} z}{\mathrm{d} x}=240-2\times \frac{x}{20}$

$x=2400$

maximum Profit $z=2,16,000$

(c)Now company decided to tax the company $ 55 for each set

Profit $(z_1)=xp(x)-c(x)-55x$

$z_1=300x-\frac{x^2}{20}-72000x-60x^2-55x$

$z_1=185x-\frac{x^2}{20}-72,000$

differentiate Profit to get maximum value

$\frac{\mathrm{d} z_1}{\mathrm{d} x}=0$

$\frac{\mathrm{d} z_1}{\mathrm{d} x}=185-\frac{2x}{20}=0$

$x=1850$

$P(z_1\ at\ x=1850)=99125$

company should charge 207.5 $ for each set

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3 years ago