Answer:
Alberta's total overtime pay of the week was $ 145.80.
Step-by-step explanation:
Given that Alberta worked 6 hours at time-and-a-half pay, and 3 hours at double-time pay, and that the value of her regular work hour is $ 9.72, to determine the value of the pay of his overtime, the following equation must be performed:
6x1.5x9.72 + 3x2x9.72 = X
9x9.72 + 6x9.72 = X
87.48 + 58.32 = X
145.8 = X
Therefore, Alberta's total overtime pay of the week was $ 145.80.
6x^2+14x+4
First factor out all numerical factors (=2 in this case)
2(3x^2+7x+2)
look for m,n such that m*n=3*2, m+n=7 => m=6, n=1
2(3x^2+6x + 1x+2)
Factor 3x^2+6x into 3x(x+2)
2( 3x(x+2)+1(x+2) )
factor out common factor (x+2)
2(x+2)(3x+1)
=>
6x^2+14x+4=2(x+2)(3x+1)
x = (180 - 55) + (180 - 25) = 280°
Answer: x = 280°
