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3 years ago

What’s the exponential form of 64

Mathematics

1 answer:

Kobotan [32]3 years ago

7 0

The exponential form of 64 is $8^{2}$ .

The square root of 64 is 8. So 8 x 8 = 64.

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Molly measured the diameter of her bike tire and found that it was 2 feet across. She estimated that for every turn of the tire,

natulia [17]

Answer:

Molly's estimation was approximately correct.

Step-by-step explanation:

Given:

Diameter of bike tire = 2 feet

Also Given:

She estimated that for every turn of the tire, the bike traveled about 6 feet.

Estimated Distance traveled = 6 feet

We need to find that whether her estimation reasonable.

Solution:

Now we know that Distance traveled is equal to Circumference of tire.

Since Tire is in circular shape.

We can say that;

Circumference of the tire will be π times diameter.

framing in equation form we get;

Circumference of the tire = $\pi \times 2 = 6.28 \ feet$

Now The actual distance traveled is 6.28 feet and Molly estimated as 6 feet.

Hence we can say that Molly's estimation was approximately correct.

5 0

3 years ago

Which ordered pair is a solution of the equation?<br> 7x-2y=-57x−2y=−5

Yuri [45]

Answer:

what ordered pairs?

Step-by-step explanation:

6 0

3 years ago

Carla is arranging square patches of grass on her rectangular lawn her lawn is 10 yards wide and 3 and 1/2 yards long how many s

Paraphin [41]

Answer:

I don't know if this is correct but wouldn't it be 560?

Step-by-step explanation:

If you have 10 on one side, you divide 10 by 1/4 to get 40. So you need 40 blocks to fill one side, and 3 1/2 on the other only needs 14. 14*40=560.

8 0

3 years ago

the mgf of a random variable x is e^3(e^t-1). Find P[mean - standard deviation squared < X < 1/2( mean + standard deviatio

postnew [5]

The given MGF is that for a random variable following a Poisson distribution with parameter $\lambda=3$ .

This means $\mathbb E(X)=\mathbb V(X)=\lambda$ , and $X$ has PMF

$f_X(x)=\begin{cases}\dfrac{3^xe^{-3}}{x!}&\text{for }x\ge0\\0&\text{otherwise}\end{cases}$

So, the desired probability is

$\mathbb P\left(\lambda-\lambda^2$

This is equivalent to

$\displaystyle\sum_{x=0}^2\mathbb P(X=x)=\sum_{x=0}^2\frac{3^x}{x!e^3}=\frac{17}{2e^3}\approx0.4232$

8 0

4 years ago

How many arrangements of three letter can be formed from the letters of the word MATH if anyletter will not be used more than on

Mariulka [41]

Combinations = n! / (n - r)! r!

$C\text{ = }\frac{n!}{(n-r)!\text{ r!}}\text{ }$

In this case:

n = 4

r = 3

Combinations = 4! /(4-3)! 3! = 24/(1)(6) = 24/6 = 4

Answer:

4 arrangements

7 0

1 year ago