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3 years ago

What uses numbers, variables and operations symbol?

1 answer:

Nutka1998 [239]3 years ago

6 0

Sounds like "formulas"! y = ax^2 + bx + c involves the variable x and the constants {a, b, c}. The "2" indicates "squaring function."

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Square had a radius of 5 square root 2 find the apothem

Karo-lina-s [1.5K]

Answer:

Apothem = 5 inches

(circum)radius = 5*sqrt(2) inches

Step-by-step explanation:

6 0

3 years ago

Which The following radical functions is graphed below

maks197457 [2]

Answer:

Option A

Step-by-step explanation:

From the graph attached,

Vertical asymptote of the given function → x = -4

Horizontal asymptote → y = 0

Oblique asymptote → None

Therefore, graph that has been given in the picture is,

F(x) = $\frac{1}{(x+4)^2}$

Option (A) will be the answer.

5 0

3 years ago

Hey guys, I need help with these questions. I need them done by today! Please, help :( There are 4 questions or more I think, I

Orlov [11]

Answer:

Step-by-step explanation:

Domain x^2 - 9 {Solution: - infinity < x < infinity}

Interval notation (- infinity, infinity)

Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)

Interval notation (-9, infinity)

Axis interception points of x^2 - 9:

X- intercepts (3, 0) (-3, 0)

Y-intercepts (0, -9)

Vertex of x^2 - 9: Minimum (0, -9)

Solve for f:

f (x) = x^2 - 9

Step 1: Divide both sides by x.

fx / x = x^2 - 9 / x

f = x^2 - 9 / x

Answer:

f = x^2 - 9 / x

8 0

1 year ago

The equation d = d equals StartFraction m Over V EndFraction. can be used to calculate the density, d, of an object with mass, m

Alisiya [41]

Answer:

m/d = V

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9

elena55 [62]

Step-by-step explanation:

$\frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1$

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

${c}^{2} = {a}^{2} - {b}^{2}$

Here a^2 is 9, b^2 is 4.

${c}^{2} = 9 - 4$

${c}^{2} = 5$

$c = \sqrt{5}$

So our foci is

$(2, - 5 + \sqrt{5} )$

and

$(2, - 5 - \sqrt{5} )$

6 0

2 years ago