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Pachacha [2.7K]
3 years ago
13

Trevor bought 8 gallons of paint to paint hishouse. He used all but 1 quart. How manyquarts of paint did Trevor use? (Lesson 10.

4)CA 7 quarts(C 31 quartsB 15 quartsD 47 quarts

Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
4 0
We know that 4 quarts is a gallon and 4x8=32, and he only used one quart so it would be C, 31. 
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Your science quiz had 17 questions and you answered 13 of the questions correctly. What is your present score?
konstantin123 [22]

dived 13 by 17

13/17 = 0.7647

  = 76.47%

 if you need to round the number it would be 76%, which is a 76 grade

7 0
4 years ago
The equation cos (35 degree) equals StartFraction a Over 25 EndFraction can be used to find the length of Line segment B C. What
valentinak56 [21]

Incomplete Question the complete Question with figure is below.

Answer:

Therefore the length of line Segment BC is 20.5 in.

Step-by-step explanation:

Given:

In Right Angle Triangle ABC

∠C = 90°

∠B = 35°

BC = a

AB = hypotenuse = 25

\cos 35\°=\dfrac{a}{25}

To Find:

BC = ?

Solution:

In Right Angle Triangle ABC , Using Cosine Identity we get

\cos B = \dfrac{\textrm{side adjacent to angle B}}{Hypotenuse}\\

Substituting we get

\cos 35 = \dfrac{a}{25}\\\\a=25\times 0.8191=20.47\\\\a=20.5\ in

Therefore the length of line Segment BC is 20.5 in.

5 0
3 years ago
Read 2 more answers
What is a simplified form of the expression (5^2)-^2Divided by 5^3
laila [671]

Answer:

5^ -7  =1 / 5^7

Step-by-step explanation:

(5^2)-^2/ 5^3

We know that a^b^c = a^(b*c)

(5^2)-^2 = 5^(2*-2) = 5^-4

5^-4/  5^3

We know that a^b /a^c = a^ (b-c)

5 ^ (-4-3)

5^ -7

If we don't want to use negative exponents

We know that a^ -b = 1/ a^b

1 / 5^7

7 0
3 years ago
What is the equation of the axis of symmetry of the graph of y+3x_6=-3(x_2)+4
agasfer [191]
Aos= -b/2a so plunin your numbers and you'll get the AOS so you can find the vertex
7 0
3 years ago
Question 1: The diagonal of a rectangle, with base x, remains at a fixed
kramer

We have that The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

From the question we are told

The diagonal of a rectangle, with base x, remains at a fixed value of 3cm. If the base is increasing at a rate of 8 cm/s. at what rate is  the height changing when the length of the base is 2 cm?

Generally the Pythagoras equation for the triangle   is mathematically given

as

r^2=h^2+x^2

With r=3

Therefore

dx/dt=8cm/s

Hence

2rdr/dt=2hdh/dt+2xdx/dt\\\\\dh/dt=\frac{-x}{r^2-x^2}dx/dt

We  have

dh/dt=-2/\sqrt{5}(8)\\\\dh/dt=-7.2cm/s

Therefore

The height changing rate  when the length of the base is 2 cm

dh/dt=-7.2cm/s

For more information on this visit

brainly.com/question/23366835

4 0
3 years ago
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