The answer is D.
the base of the pyramid is lxh which is .75 x .75 = 0.5625
Each of the sides are triangles which are 1/2 bxh which equals .6/2 = .3
there is 4 triangular sides so .3 x 4 = 1.2
and 1.2 + 0.5625 = 1.7625.
Step-by-step explanation + Answer:
x = 1st job
y = 2nd job
x + y = 22......x = 22 - y
7x + 8.25y = 171.50
7(22 - y ) + 8.25y = 171.50
154 - 7y + 8.25y = 171.50
-7y + 8.25y = 171.50 - 154
1.25y = 17.50
y = 17.50 / 1.25
y = 14 <== 14 hrs at the 8.25 per hr job
x + y = 22
x + 14 = 22
x = 22 - 14
x = 8 <=== 8 hrs at the 7 per hr job
All we need to do is to find a common denominator for both 1/2 and the other numbers individually:
1/2 = 3/6 (so 3/6 is not less than 1/2 - both numbers are equal)
1/2 = 15/30 and 7/15 = 14/30 (so 7/15 is less than 1/2)
1/2 = 9/18 and 4/9 = 8/18 (so 4/9 is less than 1/2)
1/2 = 4/8 (so 5/8 is not less - it's greater than 1/2)
Answer: From the list above only <u>7/15 and 4/9</u> are less than 1/2.
With the frequecy distribution shown in the 50 cities of pakistan,
- range = 18
- mean = 18.1
- median = 19.8333
- mode = 19.125
- kurtosis = 2.7508
- Standard deviation = 3.75
<h3>
How to find the Range</h3>
= highest value - lowest value
= 26.5 - 8.5
= 18
<h3>
How to find the mean</h3>
= ∑ f x / ∑ f
= ∑ f x / N
= 905 / 50
= 18.1
median
= lower limit + ( N/2 - C ) * h / ( frequency of the class interval )
C = cumulative frequency preceeding to the median class frequency
h = class interval
= 18.5 + ( 50 / 2 - ( 5 + 12 ) ) * 3 / 18
= 18.5 + 1.3333
= 19.8333
<h3>
How to find the mode</h3>
The mode is the value with the highest frequency occurence. This is under class 18 - 20
mode = lower limit + ( ( f1 - f0 ) / (2*f1 - f0 - f2 ) ) * h
f1 = fequency of the modal class
f0 = freqency of the preceeding modal class
f2 = frequency of the next modal class
h = class interval
= 18.5 + ( ( 18 - 12 ) / (2 * 18 - 12 - 8 ) ) * 3
= 18 + ( 0.375 ) * 3
= 19.125
<h3>
How to find the standard deviation </h3>
= sqrt ( 1 / N ∑ f ( x - x' )^2 )
= sqrt (1 / 50 * 706.5
= 3.7589
<h3>
How to solve for relative dispersion </h3>
= standard deviation / mean
= 3.7589 / 3
= 1.2530
<h3>
What is the variance? </h3>
= ( standard deviation )^2
= ( 3.7589 )^2
= 14.1293
<h3>
How to solve for kurtosis</h3>
= ∑ f ( x - x' )^4 / ( N * ( standard deviation )^4 )
= 27459.405 / ( 50 * 3.7589^4 )
= 2.7509
Read more on frequency distribution here: brainly.com/question/1094036
Answer:
Step-by-step explanation:
15 + 720 is 1120