Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.
The slope (m) = -13.
We can use the slope formula:
m = (y2 - y1) / (x2 - x1)
Let (x1, y1) = (7, 26)
(x2, y2) = (12, -39)
Plug in the values into the formula:
m = (y2 - y1) / (x2 - x1)
m = (-39 - 26) / (12 - 7)
m = -65/5
m = -13
Greatest To Least 1. AC 2. BC 3. AB
Answer:If shoes are for all games in row, P
=
2
+
3
g
If not, P
=
5
g ,with g the number of games
Explanation:
The price depends:if shoes are included for the whole games, you just have to pay them once and then you have to pay
g
g
a
m
e
s
, so P
(
g
)
=
2
+
3
g Else, you have to pay g
s
h
o
e
s and g
b
o
w
l
p
a
r
t
y
,so
P
(
g
)
=
2g
+
3
g⇔
P
(
g
)
=
5
g
- <u><em>Hope this helped hope you get a good score on your assignment/test/quiz/homework</em></u>
<u><em></em></u>
<u><em></em></u>
<h2><u><em>
-Tay did this</em></u></h2>
