A = 2bs + b^2; where A = area of pyramid; b = base length; s = the slant height;
136 = 8s + 16 ;
8s = 120;
s = 15 inches;
Answer:
L = 324 cm²
S = 359.1 cm²
Step-by-step explanation:
Lateral surface area of a triangular prism is given by,
Lateral surface area = Perimeter of the triangular base × Height
= (9 + 9 + 9)×12
= 27 × 12
= 324 cm²
Surface area area of the triangular prism = Lateral area of the prism + Area of the triangular bases
= 324 + ![\frac{1}{2}(Base)(Height)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%28Base%29%28Height%29)
= 324 + ![\frac{1}{2}(9)(7.8)](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%289%29%287.8%29)
= 324 + 35.1
= 359.1 cm²
Answer:
![\hat p=0.645\\\\ME=0.233\\\\x=645 \ individuals](https://tex.z-dn.net/?f=%5Chat%20p%3D0.645%5C%5C%5C%5CME%3D0.233%5C%5C%5C%5Cx%3D645%20%5C%20individuals)
Step-by-step explanation:
-Given the boundaries as 0.412 and 0.878
-
is the point estimate for the population proportion and is calculated as follows:
![\hat p=\frac{Upper \ Bound+Lower \ Bound}{2}\\\\=\frac{0.878+0.412}{2}\\\\=0.645\\\\](https://tex.z-dn.net/?f=%5Chat%20p%3D%5Cfrac%7BUpper%20%5C%20Bound%2BLower%20%5C%20Bound%7D%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B0.878%2B0.412%7D%7B2%7D%5C%5C%5C%5C%3D0.645%5C%5C%5C%5C)
#The margin of error, ME can be calculated for the confidence intervals using the formula:
![ME=\frac{Upper \ Bound-Lower \ Bound}{2}\\\\=\frac{0.878-0.412}{2}\\\\=0.233](https://tex.z-dn.net/?f=ME%3D%5Cfrac%7BUpper%20%5C%20Bound-Lower%20%5C%20Bound%7D%7B2%7D%5C%5C%5C%5C%3D%5Cfrac%7B0.878-0.412%7D%7B2%7D%5C%5C%5C%5C%3D0.233)
#The number of individuals in the sample is the product of the point estimate and population size:
![\hat p=\frac{x}{n}\\\\x=\hat pn\\\\=0.645\times 1000\\\\=645](https://tex.z-dn.net/?f=%5Chat%20p%3D%5Cfrac%7Bx%7D%7Bn%7D%5C%5C%5C%5Cx%3D%5Chat%20pn%5C%5C%5C%5C%3D0.645%5Ctimes%201000%5C%5C%5C%5C%3D645)
Hence, there are 645 individuals in the sample.
Answer:
65536
Step-by-step explanation:
multiply each term by 2 until you get to the 14th term. the 14th term is 65536