Denote the unit vectors of R^3 by . Now consider and . We have that . Also, the vector is not a linear combination of because any linear combination of these two vectors will have third coordinate zero, but v_3 has third coordinate 1 so they can't be equal.
However, the set is not linearly independent, because is a non-trivial linear combination of these vectors that equals zero.
This is my interpretation of bias, something that screws your acceptance of other people's view, and taking <span>into account only one view point. </span>