-5x − 4 = -29<br> what is x

PLZZZZ HELP WITHT THISSSS

IRISSAK [1]

Answer:

lol idk my butthole stinke

Step-by-step explanation:

7 0

3 years ago

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How to do this question

Dafna11 [192]

Answer:

$0$

Step-by-step explanation:

Given:

$f(x) = \begin{cases} -x -2 &, &x < 0 \\ x &, &0 \leqslant x < 3 \\ x^2 -1 &, &3 \leqslant x \end{cases}$

Solving for $f(0)$ :

$f(0) = x \text{ when } x = 0 \\ f(0) = 0$

6 0

3 years ago

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What is the value of x in the equation –x = 2 – 3x + 6?

Aneli [31]

Answer:

x=4

Step-by-step explanation:

Let's solve your equation step-by-step.

−x=2−3x+6

Step 1: Simplify both sides of the equation.

−x=2−3x+6

−x=2+−3x+6

−x=(−3x)+(2+6)(Combine Like Terms)

−x=−3x+8

Step 2: Add 3x to both sides.

−x+3x=−3x+8+3x

2x=8

Step 3: Divide both sides by 2.

2x/2 = 8/2

x=4

6 0

3 years ago

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Can you help me answer this question

r-ruslan [8.4K]

Division of a fraction is the equivalent of multiplying by its reciprocal
ex.
$\frac{\frac{A}{B} }{\frac{C}{D}}=\frac{A}{B} *\frac{D}{C}$
i suggest you try to remember this concept

in terms of your question

$\frac{\frac{4c-12}{4c+8}}{\frac{c-3}{c^2-4}}= \frac{4c-12}{4c+8} *\frac{c^2 -4}{c-3}$

from this point, just multiple the numerators together and denominators together, then simplify if necessary

fyi- difference of squares
$x^2-b^2 = (x-b)(x+b)$
relating that to
$c^2-4 = c^2 -2^2 = (c-2)(c+2)$

also a side note, you might want to factor out the 4 first in the top fraction

4 0

4 years ago

Greetings. As a beginner, I'm struggling a bit to learn calculus. May I know what is the derivative of x to the power 4 step by

elena-14-01-66 [18.8K]

If you're just starting calculus, perhaps you're asking about using the definition of the derivative to differentiate $x^4$ .

We have

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x+h)^4 - x^4}h$

Expand the numerator using the binomial theorem, then simplify and compute the limit.

$\dfrac{d}{dx} x^4 = \displaystyle \lim_{h\to0} \frac{(x^4+4hx^3 + 6h^2x^2 + 4h^3x + h^4) - x^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} \frac{4hx^3 + 6h^2x^2 + 4h^3x + h^4}h \\\\ ~~~~~~~~ = \lim_{h\to0} (4x^3 + 6hx^2 + 4h^2x + h^3) = \boxed{4x^3}$

In general, the derivative of a power function $f(x) = x^n$ is $\frac{df}{dx} = nx^{n-1}$ . (This is the aptly-named "power rule" for differentiation.)

3 0

2 years ago

-5x − 4 = -29 what is x