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mrs_skeptik [129]
3 years ago
11

Can you help me answer this question

Mathematics
1 answer:
r-ruslan [8.4K]3 years ago
4 0
Division of a fraction is the equivalent of multiplying by its reciprocal
ex.
\frac{\frac{A}{B} }{\frac{C}{D}}=\frac{A}{B} *\frac{D}{C}
i suggest you try to remember this concept

in terms of your question

\frac{\frac{4c-12}{4c+8}}{\frac{c-3}{c^2-4}}= \frac{4c-12}{4c+8} *\frac{c^2 -4}{c-3}

from this point, just multiple the numerators together and denominators together, then simplify if necessary

fyi- difference of squares
x^2-b^2 = (x-b)(x+b)
relating that to
c^2-4 = c^2 -2^2 = (c-2)(c+2)

also a side note, you might want to factor out the 4 first in the top fraction


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